Physics: Post your doubts here!

[SIstudy]

That's how we draw triangle. How do you draw it?

umm don't we draw it this way

 

[Thought blocker]

umm don't we draw it this way

I actually don't remember what I did. I need to read the question. Which paper is it?

 

[SIstudy]

I actually don't remember what I did. I need to read the question. Which paper is it?

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s10_qp_21.pdf
Q2 B (ii)

 

[Thought blocker]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s10_qp_21.pdf
Q2 B (ii)

Okay that part.
Here, I did that coz the graph was curved, how can you do like that? If it is curved your answer will be wrong. You obviously need to draw a tangent.
Um, its like drawing a tangent you get gradient here for curve graphs.

 

[SIstudy]

Okay that part.
Here, I did that coz the graph was curved, how can you do like that? If it is curved your answer will be wrong. You obviously need to draw a tangent.
Um, its like drawing a tangent you get gradient here for curve graphs.

I'm doin by tangent then im getting my answer as 2.25 which is out of range
the range given in mark scheme is 2.8± 1

 

[Thought blocker]

I'm doin by tangent then im getting my answer as 2.25 which is out of range
the range given in mark scheme is 2.8± 1

Should I explain it to you on board?
Join : http://www.twiddla.com/1831402

 

[Thought blocker]

See you send me mine work, so see it and look where are you stopped at.

 

[SIstudy]

See you send me mine work, so see it and look where are you stopped at.

umm I don't get it :/
and neither the next part of this question
nvm i'll try later
thanks fr ur help tho

 

[Thought blocker]

umm I don't get it :/
and neither the next part of this question
nvm i'll try later
thanks fr ur help tho

Look you are asked to find the speed of the ball at a time of 0.40 s yes?
So here the graph is curved so we cant do the way you did.
So the other possible way is with the help of tangent.
So, make a line touching that 0.4 above and down, make sure no other points are touched in the graph.
So that you can now calculate it from gradient as s here = change in d/ change in time. Thats simply change in y/ change in x means (y2 - y1)/(x2 - x1)

That's it.

Be calm, do it after 30 minutes. I bet you will be able to do both. If not, do tell me. I will be here to help you Sls!

 

[SIstudy]

Look you are asked to find the speed of the ball at a time of 0.40 s yes?
So here the graph is curved so we cant do the way you did.
So the other possible way is with the help of tangent.
So, make a line touching that 0.4 above and down, make sure no other points are touched in the graph.
So that you can now calculate it from gradient as s here = change in d/ change in time. Thats simply change in y/ change in x means (y2 - y1)/(x2 - x1)

That's it.

Be calm, do it after 30 minutes. I bet you will be able to do both. If not, do tell me. I will be here to help you Sls!

ahan probably I was drawin the tangent wrong lol :') #non#math#student
thank yu

 

[Thought blocker]

ahan probably I was drawin the tangent wrong lol :') #non#math#student
thank yu

You're welcome. \(^o^)/

 

[SIstudy]

You're welcome. \(^o^)/

another favor
do yu hav an excess to the s14 p1 & p2
I fail to find em anywhere :')

 

[Thought blocker]

another favor
do yu hav an excess to the s14 p1 & p2
I fail to find em anywhere :')

Variant?

 

[SIstudy]

Variant?

any variant will be appreciated
i'm lookin fr all the variants tho :')

 

[Thought blocker]

any variant will be appreciated
i'm lookin fr all the variants tho :')

Variant 1 : Here.
Variant 2 : Here.
Variant 3 : Here.

 

[SIstudy]

Variant 1 : Here.
Variant 2 : Here.
Variant 3 : Here.

Thanks ALOT

 

[TimBluesWin]

Can anybody explain to me how to do no. 7 mayjune 2009 paper 04? Thanks a lot!!

 

[SIstudy]

Physicist can yu pls help me with this
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s10_qp_21.pdf
Q2 B (ii) (iii) and Q3 (b) (iii) 2

 

[Bba321]

Please help me with qs 2 part a
http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_w08_qp_2.pdf
Why can't we take the distance as 29.3 to calculate the speed v of the car before the brakes are applied?

 

[SIstudy]

sure. but it won't right now.

I'll provide the explanations tomorrow insha Allaah

please also Q4 (B) and (C) and in Q7 c(ii) how to find volume?
(questions are of the same paper)