Physics: Post your doubts here!

[SIstudy]

all of them have been explained at

http://physics-ref.blogspot.com/2014/10/9702-june-2010-paper-21-worked.html

umm I don't get it
in Q4 part (b)if you're using the formula, means there's 2 unknowns D and n.
and isn't D 165 cm given in the question?
secondly, aren't we supposed to use this formula for double slits only?
and in Q4 part (C)
why doesn't P rotate at 90 degree as well|?

 

[manutd96]

I've added some more details there. See if it helps now, or are you still in doubts?

okay, i understand it now. thanks a lot for your help.

 

[manutd96]

I've added some more details there. See if it helps now, or are you still in doubts?

okay, i understand it now. thanks a lot for your help.

 

[Bba321]

details are available at
http://physics-ref.blogspot.com/2014/09/9702-november-2005-paper-2-worked.html

Thanks !!
Please help me with qs 5b and 6b

http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_w04_qp_2.pdf

Thanks

 

[arvin vinz]

Hi..can anyone help me with this question??

 

[SIstudy]

i've added more details. be sure to read it carefully. it's good that you clear this before the exam. I hope you identified your mistake

Oh my Godd
yes I did realize my mistake, thanks A LOT, Jazak'Allah

 

[priya_sharma]

guyzz can anyone hlp me with w12 paper 4 Q9 b (i)
the graph i dont understand how to draw it...
wat is a square wave??
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w12_qp_42.pdf
plz hlp[ me fast i have a paper to write tomrw

 

[priya_sharma]

i have added the graph at

http://physics-ref.blogspot.com/2014/07/9702-november-2012-paper-41-42-worked.html

thnxx friend can u tell me on wat topic to focus on i have my alevel physics p4 tomrw
plzz tell me wat paper to solv or any tips plzz

 

[Bba321]

Please help me with qs 5b and 6b

http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_w04_qp_2.pdf

Thanks

 

[robinhoodmustafa]

check q22 at http://physics-ref.blogspot.com/2014/10/physics-9702-doubts-help-page-4.html

the other should also look at it.

and if anyone can explain it in a more appropriate way, you are welcome to share your explanation

Can u please share the link for November 2006 doubts

 

[SIstudy]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s11_qp_21.pdf
Please help me with Q1 B (i)
and Q5 a (ii) and part b

 

[SIstudy]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w11_qp_21.pdf
Q1 c(ii) i don't understand how the area is calculated, please explain :/

 

[TimBluesWin]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_21.pdf
Please help me with Q1 B (i)
and Q5 a (ii) and part b

1b. Use formula R=(p*l)/A (p is resistivity, l is length, A is cross-sectional area of wire, use formula A=pi*(0.5*d)^2 R is resistance)
So you just input the original measurement into the equation.
5a (ii) Okay so you've found 0.667 for the minimum current. So you can draw a curve with decreasing gradient as R increases. (As V=IR) (I gave a picture of it)
5b. To find the minimum/maximum current, you need to find the minimum/maximum voltage first.
Maximum voltage: 12/12*12=12V. Hence Max current= 12V/6=2A
Minimum voltage: 0/12*12=0V. Hence min current: 0A

Hope I am right, if I'm wrong, just tell me.

 

[TimBluesWin]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w11_qp_21.pdf
Q1 c(ii) i don't understand how the area is calculated, please explain :/

Area is just either length*width, length*height, or width*height. Since the question asks about the maximum pressure, just select the two shortest sides to be multiplied to obtain maximum pressure.

 

[SIstudy]

1b. Use formula R=(p*l)/A (p is resistivity, l is length, A is cross-sectional area of wire, use formula A=pi*(0.5*d)^2 R is resistance)
So you just input the original measurement into the equation.
5a (ii) Okay so you've found 0.667 for the minimum current. So you can draw a curve with decreasing gradient as R increases. (As V=IR) (I gave a picture of it)
5b. To find the minimum/maximum current, you need to find the minimum/maximum voltage first.
Maximum voltage: 12/12*12=12V. Hence Max current= 12V/6=2A
Minimum voltage: 0/12*12=0V. Hence min current: 0A

Hope I am right, if I'm wrong, just tell me.

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s11_qp_21.pdf
fr Q5 a (ii)
how did yu draw the graph, I mean what readings yu took?

 

[SIstudy]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w11_qp_21.pdf

Q3 b (ii)
Q4 c (ii) pls show the working

 

[SIstudy]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s11_qp_21.pdf
Q1 b(ii)
please solve, showing the calculations
I tried it several times but my answer repeatedly came the same incorrect value

 

[Nasrullah Ali Baloch]

Can anyone please provide me the best notes of AS-Level Physics???

 

[SIstudy]

Can anyone please provide me the best notes of AS-Level Physics???

 

[TimBluesWin]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s11_qp_21.pdf
fr Q5 a (ii)
how did yu draw the graph, I mean what readings yu took?

I think I've attached the file; it's how I draw for no 5aii.... I recommend that you take readings for R=2 (Would give I1=1.5), R=6 (Would give I1=1) though.