Physics: Post your doubts here!

[Dark Destination]

Awesome12
Dark Destination
F.Z.M. 7
exploded diper

^^^^^ PLEASE HELP .DAMN PHYSICS

Which one is the toughest one?

And also, they are easy. Just relax. And think about them. You will eventually understand the MCQ.

 

[exploded diper]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s12_qp_13.pdf

Q 10 pls.

force due to box= 1200 N
force due to man= 800N
resultant force = 400N
total mass of man and box = 200kg
apply F=MA
A=2 m/s2
v^2 = u^2 + 2AS
where distance (s) = 9m
so v=6 m/s

 

[asadalam]

Which one is the toughest one?

And also, they are easy. Just relax. And think about them. You will eventually understand the MCQ.

I solved most of them through common sense and tukkas,but i dont get the working in all of these.

 

[Dark Destination]

I solved most of them through common sense and tukkas,but i dont get the working in all of these.

First one requires moments. It's a couple. F * 1.20 = 900 * 0.20 ?

 

[asadalam]

First one requires moments. It's a couple. F * 1.20 = 900 * 0.20 ?

First one requires moments. It's a couple. F * 1.20 = 900 * 0.20 ?

So they are both couples?And i cant really understnad whe were multiplying 900 with 0.2,even though i know thats how we have to do it.Care to elaboratE?

 

[Dark Destination]

So they are both couples?And i cant really understnad whe were multiplying 900 with 0.2,even though i know thats how we have to do it.Care to elaboratE?

See exploded dipers diagram. 0.20 is the perpendicular distance.

 

[exploded diper]

See exploded dipers diagram. 0.20 is the perpendicular distance.

explain 29
and in 21 will we take area under the graph..

 

[Dark Destination]

explain 29
and in 21 will we take area under the graph..

29. It's because the charged particle is not being moved towards the center, work is not being done against any force.

 

[asadalam]

explain 29
and in 21 will we take area under the graph..

How does area under the graph give the answer?

 

[Dark Destination]

How does area under the graph give the answer?

Haven't you read the book? I read it just yesterday, and this was there. Area under graph is work done.

 

[exploded diper]

Haven't you read the book? I read it just yesterday, and this was there. Area under graph is work done.

but wouldnt we multiply it by 10 after tht... cuz we need the force not the mass....cuz i am getting 0.29 tht way

 

[exploded diper]

29. It's because the charged particle is not being moved towards the center, work is not being done against any force.

explain a bit more.....

 

[asadalam]

Haven't you read the book? I read it just yesterday, and this was there. Area under graph is work done.

TBH,no

 

[Dark Destination]

explain a bit more.....

In this universe, work is done against a force.

When you raise a stone through height H, you are applying force MG on it.. and work is being done against the force of gravity. Now that work appears in the form of STORED gravitational potential energy!

Same way, work is done in a spring. You do work in compressing the spring, you do work against the stiffness of the spring, and it is stored in the form of elastic potential energy.

There is Electric potential energy too. When a charge moves against a field. If you push a proton towards a positive plate, you are doing work against electrostatic repulsion so it will be stored as Electric potential energy. Work done to push it = Electric potential energy stored in it.

Now figure out the question..

 

[exploded diper]

So they are both couples?And i cant really understnad whe were multiplying 900 with 0.2,even though i know thats how we have to do it.Care to elaboratE?

for Q#7

 

[asadalam]

for Q#7

Yeah thanks for that,though i figured it myself after reading the book.
Reading can do wonders
I actually did it by taking relative velocities,1 ms-1 and 0 and then using previous knowledge that if an object moves towards another one with same mass,their speed is halved and mass doubled,so thats how i did it but this seems more simple so thanks!

 

[exploded diper]

Yeah thanks for that,though i figured it myself after reading the book.
Reading can do wonders
I actually did it by taking relative velocities,1 ms-1 and 0 and then using previous knowledge that if an object moves towards another one with same mass,their speed is halved and mass doubled,so thats how i did it but this seems more simple so thanks!

so u done all of em?

 

[asadalam]

so u done all of em?

Na i still need help with the rest

 

[princess Anu]

 

[Awesome12]

why is b...View attachment 49684

The reaction force is always perpendicular to the surface. In this case, there are two forces acting:
1 - The horizontal force in the right direction causing the car to move forward
2 - The upward reaction force

Since both of the forces are acting simultaneously, we will take their resultant, which is the answer shown in option B.