- Messages
- 1,229
- Reaction score
- 740
- Points
- 123
what is the assumption supposed to be in part two?
-
We need your support!
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
Physics: Post your doubts here!
- Thread starter XPFMember
- Start date
- Messages
- 1,229
- Reaction score
- 740
- Points
- 123
what are the effects of increasing slit width keeping slit separation constant ?( in double slit experiment) apart from greater brightness of Bright fringes?
no change to fringe separation
- Messages
- 90
- Reaction score
- 34
- Points
- 28
can anyone answer this question plz ???????
- Messages
- 499
- Reaction score
- 584
- Points
- 103
http://theallpapers.com/papers/CIE/AS_and_ALevel/Physics (9702)/9702_w12_qp_22.pdf
Q. 7 ) e).. please
thnx.
Q. 7 ) e).. please
thnx.
- Messages
- 924
- Reaction score
- 1,096
- Points
- 153
One reaction produces 13.8MeV of energy.
13.8MeV = 13.8 x 1.6 x 10^-19 x 10^6 = 2.208 x 10^-12 J
So one reaction makes that much energy.
We want 60J per second. (60W)
So number of reactions required per second = 60J / 2.208 x 10^-12 J = 2.7 × 1013
- Messages
- 1,229
- Reaction score
- 740
- Points
- 123
is it true that fewer fringes will be observed?
- Messages
- 499
- Reaction score
- 584
- Points
- 103
Got it. Thanks.
- Messages
- 31
- Reaction score
- 3
- Points
- 18
About rounding up in AS physics paper 2....
There are a lot of calculation questions in physics, right? Also, there are many parts in each questions, and some of them are continuous, so we have to use the answer of the previous answer. For that case, the result is sometimes different from the marking scheme due to rounding up from the previous part, right? Thus, would they recognize it and mark it as right even if it's different from the marking scheme? I really want to know it because those kind of things look random in mark scheme for me, they sometimes use rounded up answer and sometimes they don't.
There are a lot of calculation questions in physics, right? Also, there are many parts in each questions, and some of them are continuous, so we have to use the answer of the previous answer. For that case, the result is sometimes different from the marking scheme due to rounding up from the previous part, right? Thus, would they recognize it and mark it as right even if it's different from the marking scheme? I really want to know it because those kind of things look random in mark scheme for me, they sometimes use rounded up answer and sometimes they don't.
No. When you increase the width of the slit, you are increasing the intensity of the light. So the results will be that the bright fringes are brighter, no change to the dark fringe and no change to fringe separation. If there are lesser bright fringes then the fringe separation would change.
- Messages
- 1,229
- Reaction score
- 740
- Points
- 123
In absence of air, time to reach max height = time to reach ground, right?
In presence of air, time to reach max height > time to reach ground?
In presence of air, time to reach max height > time to reach ground?
- Messages
- 132
- Reaction score
- 133
- Points
- 53
How to find out phase difference?
- Messages
- 924
- Reaction score
- 1,096
- Points
- 153
1. Momentum = 0.2kg * 8 ms^-1 = 1.6 kgms^-1
2. Momentum is never gained or lost. Such illusions may be created in a case like this, where a ball with momentum suddenly loses it all. However, as the ball gains momentum as it comes closer to the earth (because it accelerates) the earth is also gaining momentum in the opposite direction towards the ball. We don't notice this because this is a very small amount due to massive size of earth (my book said half diameter of an atom or something).
Similarly, energy is neither created nor destroyed. However, kinetic energy is not always conserved, since it may be converted to other forms. In inelastic collisions like this, kinetic energy was converted to heat energy.
- Messages
- 924
- Reaction score
- 1,096
- Points
- 153
Let v be velocity of neutron. Total momentum before = total momentum after
1u * 6.5*10^5 + 12u * 0 = 1u * v + 12u * 1.00*10^5
Let's just divide by u on all terms:
6.5*10^5 = v + 1.2*10^6
v = -5.5*10^5
Negative just means the neutron is moving in opposite direction.
Now since it says it's an elastic collision, we know that the kinetic energy must have been conserved. We can verify that:
Total kinetic energy before = 0.5*1u*(6.5*10^5)^2 = 2.11u*10^11 Joules
Total kinetic energy after = 0.5*1u*(-5.5*10^5)^2 + 0.5*12u*(1.00*10^5)^2 = 2.11u*10^11 joules
Hillarious! thnk uuuuuu
thanks alooooot
- Messages
- 31
- Reaction score
- 3
- Points
- 18
The answer is D so I thought it's because there is the difference in the path travelled by the waves, so there is difference in intensities, amplitudes of the waves, so there would be no complete destructive interference. But then, for the young's double slit experiment, there should be also no complete destructive interference according to what I thought, but they consider it as complete destructive interference, right?So, I was searching for it, then, I saw the explanation on the webstite, http://physics-ref.blogspot.com/2015/03/physics-9702-doubts-help-page-93.html.
They said it's because the speaker isn't point source.... what does it mean by that and how the factor 'point source' affect the result.....
Also, is my thought in the beginning wrong?
Past Exam Paper – November 2014 Paper 11 Q26
Im not sure about the point sources but the way i look at is that the middle of XY will have the highest intensity(highest peak) because its a zero order. Then as you go further from the middle, lets say to the first order the intensity gradually decreases. The 2 speakers are coherent sources, meaning they have the same amplitude and phase difference. Its the path difference between them that forms then interference pattern on the screen XY