- Messages
- 17
- Reaction score
- 4
- Points
- 13
Can anyone predict or have any idea whats coming in physics p33?
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
The elementary charge (1.6 x 10^-19) is a multiple of the differences of the given charges.
Ok guys I have a question about momentum.
Assume a scenario where two masses of equal masses and acceleration are moving towards each other about to collide.
Can we predict their behavior after collision. Do they bounce back with same velocity or acceleration? Or stick together and stay stationary? Or is it impossible to predict?
but in s2014 v 51 ths isnt the case... the lower n upper ends are till the plotted points... they r nt extended... :/extend it
he said nthng abt p 5.. (-_-)...
I don't know. If it's from the markscheme, it says the lower end should PASS between ...... In my opinion, if this end at that point, the MS should have said 'the lower end should BE at point ....' + we don't know if the line is exactly at a point, there could be an error at that point?
actually, i haven't yet read much about how the practical papers should be tackled, so I can't help here (can't be 100% sure what to do here).
What did your teacher say about these?
...
I don't know. If it's from the markscheme, it says the lower end should PASS between ...... In my opinion, if this end at that point, the MS should have said 'the lower end should BE at point ....' + we don't know if the line is exactly at a point, there could be an error at that point?
actually, i haven't yet read much about how the practical papers should be tackled, so I can't help here (can't be 100% sure what to do here).
What did your teacher say about these?
Apply 2as=v^2-u^2A cannon fires a cannonball with initial speed v at angle α to the horizontal.
Which equation is correct for the maximum height H reached?
A H = v sinα / 2g
B H = g sinα / 2v
C H = (v sinα)2 / 2g
D H = g2 sinA / 2v
i found the vertical component = Vsina ...hence, options B and D are ruled out.... but why is the answer C?
Thank you very much but what about the width of the rectangle. Im still confused about that.Just draw half rectangles with their heights at +5v and -5v since it can never exceed the supply. Each time, draw the half rectangle opposite to the vin , if the cycle of vin is +ve, draw vout at -ve and vice versa
The width depends on where Vin is 0, so everytime the graph of Vin is 0 you switch the polarity try sketching it and upload it here so I check how you sketched itThank you very much but what about the width of the rectangle. Im still confused about that.
yea but i was confused ...check at
http://physics-ref.blogspot.com/2014/07/9702-june-2013-paper-42-worked.html
bcoz at t=0, the displacement is not zero. if you plot a graph, the oscillations would correspond to a cos graph, not a sine.
for sine, when t=0, displacement is also zero
...well, this should also have been in your notes
check at
http://physics-ref.blogspot.com/2014/07/9702-june-2013-paper-42-worked.html
bcoz at t=0, the displacement is not zero. if you plot a graph, the oscillations would correspond to a cos graph, not a sine.
for sine, when t=0, displacement is also zero
...well, this should also have been in your notes
is this how i should do it ?The width depends on where Vin is 0, so everytime the graph of Vin is 0 you switch the polarity try sketching it and upload it here so I check how you sketched it
I really need help with this concept:
http://prntscr.com/75vq5i
may june 11 42 q9 b.
how do we identify across which resistor is the input going to be?
for example, in this case. is the 4.5V going to go to the Non-iverting input from across the 1kV resistor or the strain gauge?
A generalised explanation is needed on this thing,not this question specific. since I struggle on every question of this kind.
Thanks a lot and God Bless!
cn u post an example so that explaining it gets easier...Could someone just give me a quick explanation with tips on how I should find the area under a graph when I'm asked to do so? Do I count the squares? Then what? Thank you
thank you soo much!it is going across 1 kΩ resistor.. in such questions u'll always apply the concept of potential divider... the resistor n strain gauge acts as potential divider to the non-inverting input... that's y u cn see that the voltage across 1.0 kΩ is V1 ..ths is clearly indicated in the diagram...
View attachment 53800
just lyk the potential divider lyk above... instead of Vout lets suppose that it's V2
so the value of V2 is calculated as=> V2 = [(R2) / (R1 + R2) ] x Vin
the concept is very easy... just ignre the rest of the connections n focus on the wire that has strain gauge n resistor across it...
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now