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Physics: Post your doubts here!

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Cause it has to be the same in both motions ; the moon doesn't have an atmosphere so there is no air resistance on the moon
can you please elaborate :)
the upward & downward motions?
if so, then why
isn't it the case even with air resistance too ? :p
 
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can you please elaborate :)
the upward & downward motions?
if so, then why
isn't it the case even with air resistance too ? :p
For upward motion you know what the path should be like (shown in A and C)
-On the earth, while going up, the golf ball is hit with a force, while coming down it falls freely but then there is air resistance opposing it so it the curve is shorter that while going up (acceleration is less than free-fall; a<9.81)
-On the moon, while going up, same as earth the ball is hit with a force
while coming down also it falls freely but this time there is no air resistance opposing it's motion so the curve is same/similar to the one while going upwards (acceleration is same as freefall on moon)
 
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For upward motion you know what the path should be like (shown in A and C)
-On the earth, while going up, the golf ball is hit with a force, while coming down it falls freely but then there is air resistance opposing it so it the curve is shorter that while going up (acceleration is less than free-fall; a<9.81)
-On the moon, while going up, same as earth the ball is hit with a force
while coming down also it falls freely but this time there is no air resistance opposing it's motion so the curve is same/similar to the one while going upwards (acceleration is same as freefall on moon)
do u mean while going upwards there is no air resistance? and the acceleration is 9.81 ( on earth)? its only during downward motion that the acc decreases? :eek:
 
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do u mean while going upwards there is no air resistance? and the acceleration is 9.81 ( on earth)? its only during downward motion that the acc decreases? :eek:
No! There is air resistance while going up but an initial force is applied so it will travel further than during free fall
I'm sorry I'm not exactly sure how to explain this! :S
 
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while moving up there is air resistance thats why at highest point velocity is zero when moving down if the object reches terminal velocity zero acceleration otherwise acceleration increases:):)
 
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Why am I getting 13.75 instead of 15?
R= 12/3.2= 3.75
1/10+ 1/10+ 1/x= 3.75
x= 13.75
 

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Someone please explain how to do s11 paper 11 question 3 and 9.
3. Horizontal force is 3.0 N and vertical is 5.0 N. Apply Pythagoras. Square both and add to get 34. Take square root to get 5.8 N.

9. Momentum remains same before and after collision so momentum is mv.
Total mass will be 2m and so the velocity after collision will be 1/2 v. Apply 1/2 mv^2 to get 1/4 mv^2 as kinetic energy after collision.
 
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Can someone explain how to get maximum and minimum resultants of three forces e.g 3N, 4N and 5N. How the minimum is zero?
 
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upload_2015-5-25_19-30-3-png.54051


I thought X and Y is actually the plastic region??
as shown here:
upload_2015-5-25_19-30-47-png.54052


But then the answer is D :/ ???
 
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