Physics: Post your doubts here!

[69ermalik007]

Need help with this question....

 

[nehaoscar]

Why A? Wouldn't it be D?

after collision, mass = 2m
so 0.5 x 2m x v^2 = mv^2

and momentum
= 2mv^2?

But then why is it A?

 

[Ahmed Aqdam]

View attachment 54321
Why A? Wouldn't it be D?

after collision, mass = 2m
so 0.5 x 2m x v^2 = mv^2

and momentum
= 2mv^2?

But then why is it A?

Velocity does not remain same. Momentum does.
Hence mass will be 2m so v will be v/2. So KE is 1/4 mv^2.

 

[nehaoscar]

P = I^2 R

As W is removed , Total R increases so I would increase
So then wouldn't the power across Y and Z also increase?

But it's C... Why would the power across Y and Z decrease?

 

[nehaoscar]

Has not everyone done paper 2 and practicals yet? :/

 

[Ahmed Aqdam]

Has not everyone done paper 2 and practicals yet? :/

Practical 34 is on 04 June...

 

[nehaoscar]

Practical 34 is on 04 June...

Oh! I thought everyone was left with only MCQ's

 

[nehaoscar]

How to do this one?
C

 

[bubbles1997]

Aoa. Please post your guess for the upcoming chemistry practical code 34. Thanks!
https://www.xtremepapers.com/commun...vel-practical-guess-papers.41560/#post-926251

 

[nehaoscar]

B - average ke of remaining atoms is reduced? how?

 

[Ahmed Aqdam]

View attachment 54326
B - average ke of remaining atoms is reduced? how?

The more energetic molecules leave the surface so the molecules remaining have less kinetic energy.

 

[Mathemagical]

View attachment 54326
B - average ke of remaining atoms is reduced? how?

The most energetic molecules - those which possess the most kinetic energy - have sufficient energy to break the liquid bonds and escape into the atmosphere. This leaves behind the less energetic molecules, hence reducing the average kinetic energy of the remaining molecules.

 

[nehaoscar]

How to calculate?

 

[Mathemagical]

View attachment 54327
How to calculate?

Diagram 2 shows the zero error of the instrument. To calculate the accurate reading, use the formula: Actual reading - zero error.

 

[nehaoscar]

Diagram 2 shows the zero error of the instrument. To calculate the accurate reading, use the formula: Actual reading - zero error.

But then what is the least count? and is the actual value 2.5?
I'm getting 2.38... :/

 

[nehaoscar]

Why B? Why not C?

 

[nehaoscar]

Why D?

 

[nehaoscar]

How D?

 

[nehaoscar]

How is it D?

 

[princess Anu]

why is it C?