• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Physics: Post your doubts here!

Messages
1,318
Reaction score
1,374
Points
173
upload_2015-6-5_19-37-24-png.54621

How to do this one??
 
Messages
128
Reaction score
112
Points
53
It's a series circuit, so the current will be the same all around
Add up the emf of the batteries taking in note their directions
(so add up the ones facing one direction and subtract it from the others facing the other direction)

This gives total emf = 6V
Total resistance = 1000 + 100 ohms = 1100

Current = V/I
= 6/1100
= 5.5mA

V across R1 = I x R1
= 5.5mA x 100
= 0.55V

I across R2 = as I said earlier it's a series circuit, so the current is same in all components
= 5.5mA (as calculated above)
Taking clockwise as the positive direction,
e.m.f = 1.5-1.5-1.5+1.5+1.5+1.5+1.5+1.5+1.5-1.5 = 6V

Total resistance = 1100 ohm

Current through R2 = V/R = 6/1100 = 5.5mA.

Voltage across R1 = (100/1100)*6 = 0.55V

Thanks guys :)
 
Messages
510
Reaction score
607
Points
103
What happens when the time base on the C.R.O is doubled and the Y gain is unchanged? Should the frequency remain unchanged?
 
Messages
355
Reaction score
367
Points
73
If I scored 'd' in my AS levels, and I did pretty well in paper 4 and 5 (75/100 and 27/30), then what is the maximum grade that I can score? Can I get an A?
 
Messages
4,062
Reaction score
25,658
Points
523
at the highest point, the object has no vertical velocity, but has the same horizontal velocity it had at launch

the initial KE = 1/2 m v^2 (E)

the initial horizontal velocity = v cos 45

at max height, there is no vertical velocity, so the total velocity is the horizontal velocity

therefore the KE at max height is 1/2 m (v cos45)^2 = 1/2 m v^2 0.5 --- which is half the original KE

therefore, ans is A
 
Messages
1,318
Reaction score
1,374
Points
173
Messages
924
Reaction score
1,096
Points
153
Hello ppl
Assalamu Alaikum :)
http://onlineexamhelp.com/wp-content/uploads/2013/11/9702_s13_qp_11.pdf

wat is this K-CAPTURE in Q38 ?
nd i dont get 39 :/
plz someone explain :)
K-capture is the opposite of beta-emission.
Beta-emission = one neutron turns into a proton and an electron. Result = proton number increases, atomic mass remains the same.
K-capture = electron combines with a proton and forms a neutron. Result = proton number decreases, atomic mass remains the same.
 
Messages
4,062
Reaction score
25,658
Points
523
Messages
4,062
Reaction score
25,658
Points
523
K-capture is the opposite of beta-emission.
Beta-emission = one neutron turns into a proton and an electron. Result = proton number increases, atomic mass remains the same.
K-capture = electron combines with a proton and forms a neutron. Result = proton number decreases, atomic mass remains the same.
Thankyew soo much :)
 
Top