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The same question u solved for me..Which question?
How iscalculations done??
How Fg = mg?
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The same question u solved for me..Which question?
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w12_qp_43.pdf
Q12 b(ii)
what do you mean by uninterrupted length and how do you solve this question ?
anyways, thanks.i believe some of them are already solved at the blog. try to look for them there.
i'm a bit busy currently.
here is the link http://physics-ref.blogspot.com/2015/12/a-level-physics-9702-exam-tips.htmlif you could refer to the link instead of copy-paste, i would be good.
thanks
which year is this paper?
same doubt.
m/j 10 v.42which year is this paper?
part c
bii
ii
Since it's a vector quantity and both charges are +ve the field at P due to the 2 particles are in opposite directions so the opp. signsView attachment 59394
View attachment 59395
So yes, electric field strength is a vector quantity ... But are the directions opposite coz the field lines will go INTO both the alpha particle and the proton?
And this ...
force per unit charge M1
on either a stationary charge
or a positive charge
Should we write either of the two .. or should we write 'either a stationary charge or a positive charge'??
I am so dumb :/Divide the area into small sqaures
so say a 5*5 will be 1 sqaure
count approx the no. of squares under the graph
Count the pd in 1 sqaure and multiply this by the no. of squares
so say this red box is one sqaure
View attachment 59419
then count no. under graph
I UNDERSTOOD!!!!!!!!!!!!!!!!!!!!!!! THANKS A TONNES!part c
ke = work done
1/2mv^2 = VQ
And calculate
part d
F=ma
a is max when F is max
and F=EQ
so F is max when E is max so at d=0
ii - acceleration decreases and is min at 4cm and then increases
So if u take that red box ie 5*5 sqaure the wd for that one box is E*d which is approx 2.5x10^3*1x10^-2 (we'll call this answer as Z ... I'm too lazy to work out the ans )I am so dumb :/
can u please show the steps
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