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Thanks a lot.
I forgot the question. But if the gradient of velocity-time graph is different it means the acceleration of motion at those times are different.Thanks a lot.
But why do the red and yellow lines have different gradients?
Thanx Dude..!This has summary of the topics:
https://www.xtremepapers.com/community/threads/as-and-a2-physics-summaries.42827/
WelcomeThan
Thanx Dude..!
Depends on which you have more interest in really. And they are two totally different subjects so dunno if we can compare their difficulty level. But I find chemistry questions more complicated than in physics ... especially AS.Is Physics harder than Chemistry? I'll be taking AS Physics in Nov of 2016, since I'm taking AS Chemistry, Biology and Mathematics this summer, I was wondering whether I'll find Physics even harder than Chemistry or is it better than that?
I understand...and I think I'm better interested in Physics than in chemistry! Chemistry is just a helll!!Depends on which you have more interest in really. And they are two totally different subjects so dunno if we can compare their difficulty level. But I find chemistry questions more complicated than in physics ... especially AS.
I forgot the question. But if the gradient of velocity-time graph is different it means the acceleration of motion at those times are different.
Ah yeah, it's this question.Yes I know that. Can you please tell me why are the accelerations different?
This is the question
Oh well then definitely you would find physics easier.I understand...and I think I'm better interested in Physics than in chemistry! Chemistry is just a helll!!
which subs are you taking?
Great.Few days back i searched every website i knew, no where a yearly binder with marks schemes was available.
When i was tired of finding thought why don't make one and help others.
Took me 4 hours but yes i made it .
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Time is precious waste it wisely.
I am going to share a dropbox link in 5 mins just wait.Great.
Are you going to upload here?
a - photoelectric current is the no. of photons hitting the metal causing emission - so it's dependent on intensity and not frequency (E=hf) so as f becomes greater than threshold f, current increases until some time after which it'll become constant as intensity will be constantView attachment 59421
Hey,
Could anyone please provide me with the reasoning for the following questions of the photoelectric effect:
a) In graph 2 why does increase in frequency cause current to increase at a decreasing rate?
b)In graph 3 and 4 , what does negative stopping potential imply?Like what exactly does it mean?
Please help.
Thank youuu once again! But I have a slight query if it depends on intensity then why does increase in frequency trigger initially an increase in current? Like, The way I am seeing: when we increase the frequency the electrons gain more ke so the flow faster and since current is the rate of flow of charged particles it increases.However,eventually what happens is that intensity affects the number of electrons emitted per unit time(I am right?:/ ) so since intensity is constant the current turns out to be constant as nos of electrons are same. Is my analysis correct? I am confused slightly?:/a - photoelectric current is the no. of photons hitting the metal causing emission - so it's dependent on intensity and not frequency (E=hf) so as f becomes greater than threshold f, current increases until some time after which it'll become constant as intensity will be constant
b - check here http://www.s-cool.co.uk/a-level/phy.../photoelectric-current-and-stopping-potential
Yeah the way you're writing it seems right since eventually the intensity is constant so no. of e- emitted is constant so the current will be constantThank youuu once again! But I have a slight query if it depends on intensity then why does increase in frequency trigger initially an increase in current? Like, The way I am seeing: when we increase the frequency the electrons gain more ke so the flow faster and since current is the rate of flow of charged particles it increases.However,eventually what happens is that intensity affects the number of electrons emitted per unit time(I am right?:/ ) so since intensity is constant the current turns out to be constant as nos of electrons are same. Is my analysis correct? I am confused slightly?:/
Oh and yeah the following seems a pretty silly question but the contradictory nature is perplexing me. If you have an answer as to what would be ideal?
Somehow the answers are contradictory in nature.:/ Should the answer simply be a bright spot?
Thank you.
Yeah the way you're writing it seems right since eventually the intensity is constant so no. of e- emitted is constant so the current will be constant
so yep
And for the other question that you've posted I have no idea xP
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