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Any notes?Pretty easy actually ... i mean compared to paper 4 it is really easy.
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Any notes?Pretty easy actually ... i mean compared to paper 4 it is really easy.
Don't have any of my own. But I remember reading tips and help with calculating uncertainties somewhere on the internet. Plus, there's a site with solved papers. https://docs.google.com/folderview?id=0Bx_kNsO4S1YbTEZYb09ucmVLOEE&usp=docslist_apiAny notes?
Thanks.Don't have any of my own. But I remember reading tips and help with calculating uncertainties somewhere on the internet. Plus, there's a site with solved papers. https://docs.google.com/folderview?id=0Bx_kNsO4S1YbTEZYb09ucmVLOEE&usp=docslist_api
npThanks.
Yeahh.Paper 5??
I just prefer the max min method that is the easiest and like the first thing the examiners prefer too.P5 - S15 - 51
Last question
log k = y intercept
View attachment 59535
View attachment 59536
Can anyone explain how it results in the final equation of 1/2(maxk-mink)/k ??
Like % uncertainty is just [(change in k)/k ]*100 so how to get all the 1/2 and stuff??
And also is there another way to do it??
thx broAmplitude will start decreasing so the curve's amplitude will decrease slightly in each oscillations and come to rest due to damping. Here we are asked to draw for 2 oscillations with the effect of damping, hence the time period will be similar to the orignal graph as damping has no effect on time intervals, and the peak will decreases slowly so curve will be under the loops, this is what marking scheme explains.
But then for this one we have the line of best fit and one worst fit so wouldn't the uncertainty be :I just prefer the max min method that is the easiest and like the first thing the examiners prefer too.
Yeah like by min max method I meant like the gradient of worst-gradient of best/(gradient of best) *100 like when we have a fraction to find the uncertainty we keep the numerator highest and denominator lowest.Yeah btw what you are referring to is right and the same thing I meant. That was only what I was implying like the maximum possible error answer - minimum error prone answer. Yeah the last one in ms screenshot is like the shallowest and deepest graident difference divided by two like most error prone answer extremes so then we have to divide it by 2.But then for this one we have the line of best fit and one worst fit so wouldn't the uncertainty be :
(maxk - bestk)/k *100 cause otherwise to use the min max formula we'll have to draw the other worst acceptable line and then find the k right?
The first r will be 3.84 x10^8m, since that is the distance given in the question (between earth and moon)https://b29429b14407e9cdd03a7679f73a0b12c55defa0.googledrive.com/host/0B1ZiqBksUHNYQUhMWDdWeV8xc2s/June 2012 (v2) QP - Paper 4 CIE Physics.pdf
Q1(c)(ii)
I wanna use GMm(1/r1 - 1/r2)
tell me the other radius. how to do it?
thanks.
LOL I did the same thing, just i didnt directly place the value of other radius.. xD Poor me. xDThe first r will be 3.84 x10^8m, since that is the distance given in the question (between earth and moon)
The second one will be 3.84x10^8m + 0.04m, since that will be the radius after one year has passed.
Your formula will calculate the difference in potential energy between these two.
Shahab you have to link the paper or tell the variant or post a picture of the question.Question 12 , Paper 1 , May/June 2012
Can anyone solve it for me
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s12_qp_11.pdfShahab you have to link the paper or tell the variant or post a picture of the question.
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