- Messages
- 310
- Reaction score
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- Points
- 53
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37 C?These are two very tough questions if you wanna practice.
It's D37 C?
Diffraction grating maxima are more spread because there are so many slits in grating than double slit, so more diffraction takes in grating hence creating more widely spread maxima. D grating maxima are sharper because again, there are so many slits in grating compared to the two in double slit, so more diffraction takes places so more waves can interfere and create a large amplitude(meaning sharper).
Yeah the answer is C. Just apply kirchhoff's 2nd lawans is C?
How?It's D
23: maximum pressure point is compression while minimum pressure point is rarefaction. The distance between rarefaction and compression is half the wavelength. Using v=flamda, find the wavelength and divide it by 2 to get the distance between rarefaction and compression. Wavelength will turn out to be 0.6m, so the answer is 0.3m(B).
27: you see that there is half a loop and it's a fixed string experiment. So in v=flamda, the lamda will be 0.5 which will make the equation v=0.5flamda. Now, if you want a complete wave, you would need to make the equation v=f(lamda). You can do this by increasing the frequency by 2 so that the 0.5 is cancelled out. Hence 2f is the answer(C).
28: d=1/N ---> d=1/300x1000
dsintheta=nlamda
1/300x1000 *sin90=n(600x10^-9)
n=5
This means that there are 5 orders above the central maxima and 5 below. So including the central maxima there is a total of 11 maxima(5+1+5). So the answer is C.
25: There are two sections to this question. First the train approaches the observer then the train goes away from the observer. They are asking you to find the difference in oib
Thankyou... I wasn't multiplying the moments by 2.
m= 90/60
A igView attachment 64180
ans is B...?
29 b?View attachment 64172
View attachment 64173
View attachment 64174View attachment 64175
View attachment 64176
need help, can anyone explain me how to solve these questions
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