Physics: Post your doubts here!

[Unicorn]

Can someone please explain to me how the graph would be D for question 5? Because that is what the mark scheme says but wouldn't the object be acceleratiog according to this graph?

 

[princesszahra]

where;s the question????:O

 

[Unicorn]

where;s the question????:O

whoops

 

[rz123]

correct ans is
6kms-1 <6mhr-1 <6cms-1 < 6ms-1

oooww which one r u solving princess of Mars, i asked for the momentum question. i m done with it. lazy of me to not c the notes. it says dat relative speed of approach equals to relative speed of separation so its D. hope ur doubt is clear.

 

[rz123]

Can someone please explain to me how the graph would be D for question 5? Because that is what the mark scheme says but wouldn't the object be acceleratiog according to this graph?

terminal velocity is when drag equals to the pull of gravity hence the object will travel with a uniform velocity, the discplacmeent time graph is showing us the velocity, i.e the gradient. velocity remains same after a point so it will eventually be a starlight line D option, acceleration will be zero as weight and air resistance balance each other.

bring more problems of AS.

 

[Unicorn]

terminal velocity is when drag equals to the pull of gravity hence the object will travel with a uniform velocity, the discplacmeent time graph is showing us the velocity, i.e the gradient. velocity remains same after a point so it will eventually be a starlight line D option, acceleration will be zero as weight and air resistance balance each other.

bring more problems of AS.

Thanks

 

[rz123]

Thanks

I need more problems!! Cumoon bring it people!

 

[Unicorn]

I need more problems!! Cumoon bring it people!

ok same paper question 15

 

[Abdullah syed]

Plz How to take out Uncertainty in Practicals can Someone help me in Q2b October november 2009 Paper 52 Include the absolute uncertainties.

http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_w09_qp_52.pdf

 

[rz123]

ok same paper question 15

oh i was kidding u took my word serious
anyway what i get is dat if u c in both vessels the height will decrease by half from the original height in the vessel X, means h will bcm h/4 altogether, so the answer will be B mgh/4.

 

[rz123]

Plz How to take out Uncertainty in Practicals can Someone help me in Q2b October november 2009 Paper 52 Include the absolute uncertainties.

http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_w09_qp_52.pdf

absolute uncertainty is the real uncertainty divided by 2. for example u square the time .35 it bcmz .1225 + - 0.005
(.005 is the absolute uncertainty)

 

[Abdullah syed]

absolute uncertainty is the real uncertainty divided by 2. for example u square the time .35 it bcmz .1225 + - 0.005
(.005 is the absolute uncertainty)

SorryStill Didnt Get it

 

[princesszahra]

oooww which one r u solving princess of Mars, i asked for the momentum question. i m done with it. lazy of me to not c the notes. it says dat relative speed of approach equals to relative speed of separation so its D. hope ur doubt is clear.

huH!! i solved the first one!!
i thought how duffer of u not to get that right!HEHEHEEE !!

 

[princesszahra]

hehehe!! i thought how crazy u r not to get that right!! neva minddddd

 

[rz123]

SorryStill Didnt Get it

i m sorry as well. its ok f9

 

[rz123]

huH!! i solved the first one!!
i thought how duffer of u not to get that right!HEHEHEEE !!

no u didn't. how much duffer of me? quantity and SI unit required!!!
yes dat was a piece of cake. sometimes even gr8 scientists cannot get a simple thing.

 

[unique840]

no u didn't. how much duffer of me? quantity and SI unit required!!!
yes dat was a piece of cake. sometimes even gr8 scientists cannot get a simple thing.

lol

 

[Abdullah syed]

i m sorry as well. its ok f9

Plz Can U Take out the answer And Show me

 

[rz123]

Which type of radiation will produce fringes which are the closest together? [1]
A blue light
B infrared radiation
C red light
D ultraviolet radiation

 

[rz123]

In a resonance-tube experiment, a tuning fork vibrating at
a frequency of 256 Hz is held over the open end of a tube
(as shown in the diagram).
A stationary wave can form in the air between the open end of
the tube and the surface of the water. The antinode at the open
end of the tube does not occur exactly at the end but at a small
distance c from this end. The distance c is known as the ‘endcorrection’.
The value of c for a particular tube does not
depend on the harmonic.
This experiment takes into account any errors that may occur
due to the end-correction. The tube is fully immersed into the
water. The open end of the tube is slowly raised. A loud
sound is first heard when the top of the tube is 30 cm above
the surface of the water. The next loud sound is heard when
the top of the tube is 95 cm above the water surface.
Use this information to determine the speed of sound in air.