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Physics: Post your doubts here!

code11

code11

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hey i wana know wat distance to be used in order to determin initial horizontal velocity in projectile motion ? o_O if the time is given to us
 
hussamh10

hussamh10

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iKhaled said:
help me in a question may/june 2003 Q3 b) i. :S:S:S:S

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_qp_2.pdf
Click to expand...
In first part pointer has a deflection of 6.5 degrees so by finding out the arc lenth we will get the extension by
(6.5/360)x2pi(1.5)=0.17
ii)in second part we have to find out the strain which is
Extension/Original length
iii)stess
Force/area=(6.0x9.81)/(7.9x10^-7)=7.44x10^7 Pa
Then we have to find the Young modulus which =Stress/strain
in the last part their is NO extension if the pointer comes back to its position....
 
iKhaled

iKhaled

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hussamh10 said:
In first part pointer has a deflection of 6.5 degrees so by finding out the arc lenth we will get the extension by
(6.5/360)x2pi(1.5)=0.17
ii)in second part we have to find out the strain which is
Extension/Original length
iii)stess
Force/area=(6.0x9.81)/(7.9x10^-7)=7.44x10^7 Pa
Then we have to find the Young modulus which =Stress/strain
in the last part their is NO extension if the pointer comes back to its position....
Click to expand...
dude, for the first part y we get the arc length? isn't it curved and extension can't be curved? it should be a straight line? :/
 
hussamh10

hussamh10

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iKhaled said:
dude, for the first part y we get the arc length? isn't it curved and extension can't be curved? it should be a straight line? :/
Click to expand...
extension is curved here the movement of pointer shows the extension so the only way to do is to get the arc lenth....
If you did this paper how did you got the absolute error in the first question of this paper??/
 
iKhaled

iKhaled

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hussamh10 said:
extension is curved here the movement of pointer shows the extension so the only way to do is to get the arc lenth....
If you did this paper how did you got the absolute error in the first question of this paper??/
Click to expand...
i didn't do it skipped the q :p .. but dude this question we r talking about is confusing my ass..in the mark scheme it says u can use s = r x theta...y did they use sin ?
 
hussamh10

hussamh10

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iKhaled said:
i didn't do it skipped the q :p .. but dude this question we r talking about is confusing my ass..in the mark scheme it says u can use s = r x theta...y did they use sin ?
Click to expand...
sin is an alternative way to do this by by pyrhgras theoram it is not related with Rtheta
 
Unicorn

Unicorn

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R

raamish

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hussamh10 said:
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w07_qp_2.pdf
Q1 (ii) part why the absolute obtained error is halved?
Click to expand...

THe error is halved because look at the equation: V=pier2l. So r is 2 so that means we will have to divide by 2 to get the answer of R only not 2r. But i dont get why they are adding the uncertainties and then dividing them. Shouldnt they subtract the uncertainties like this: V-L=3.3-1.5/2 to get answer????
 
M

Mattman

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