- Messages
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- Reaction score
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CAN SOMEONE PLEASE ANSWER QUESTIONS 6b and 6c
for question 6b
they tell u that the distance between where sound is heard is 32.4 and if u look closely in fig 6.1 you will see it is a node
and the distance between 2 nodes is 0.5ƛ
and we know s=f * ƛ
so 0.5ƛ=32.4cm so ƛ=64.8cm =0.648
therefore 0.648*512 =331.78 -> 332m/s
for 6c
distance between a node and antinode it is 0.25ƛ which is half distance between 2 nodes
so 32.4/2 =16.2
and the length of air is 15.7 so 16.2-15.7 =0.5 above the end of the tube or simply 16.2 cm above water level
hope it helped