Physics: Post your doubts here!

[AAAAAA]

so that the body does not fall towards the centre and it remains in an orbit

The body would not fall towards the centre but move off along a tangential path

 

[geek101]

can someone please post the 2012 paper 2 and 1?? thnx

 

[queen of the legend]

Anyone having problem in vectors or any other relative topic of physics can refer to this website:

http://www.physicsclassroom.com/Class/vectors/u3l1a.cfm

its quite helpful for clearing up concepts

 

[queen of the legend]

Re: Physics Help here! Stuck somewhere?? Ask here!

Can anyone tell me what should i learn for pressure in lquids for As level and please give me the detailed explanation of viscosity in liquids asap !!! thanks

If you are attending oct/nov exam for physics go throught the syllabus and study according to learning outcomes

besides you can check wether you should study pressure and upthrust !

 

[Minato112]

can someone please post the 2012 paper 2 and 1?? thnx

June or November?

 

[geek101]

June or November?

nov 2012..yeah please june ofc

 

[Minato112]

nov 2012..yeah please june ofc

haha srry but forgot that we were in 2012!

Paper 1.
Variant 1: http://olevel.sourceforge.net/papers/9702/9702_s12_qp_11.pdf
Variant 2: http://olevel.sourceforge.net/papers/9702/9702_s12_qp_12.pdf
Variant 3: http://olevel.sourceforge.net/papers/9702/9702_s12_qp_13.pdf

Paper 2.
Variant 1: http://olevel.sourceforge.net/papers/9702/9702_s12_qp_21.pdf
Variant 2: http://olevel.sourceforge.net/papers/9702/9702_s12_qp_22.pdf
Variant 3: http://olevel.sourceforge.net/papers/9702/9702_s12_qp_23.pdf

 

[Kumkum]

question paper: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s04_qp_2.pdf
marking scheme: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s04_ms.pdf
please help me with question 2 (b).

 

[geek101]

haha srry but forgot that we were in 2012!

Paper 1.
Variant 1: http://olevel.sourceforge.net/papers/9702/9702_s12_qp_11.pdf
Variant 2: http://olevel.sourceforge.net/papers/9702/9702_s12_qp_12.pdf
Variant 3: http://olevel.sourceforge.net/papers/9702/9702_s12_qp_13.pdf

Paper 2.
Variant 1: http://olevel.sourceforge.net/papers/9702/9702_s12_qp_21.pdf
Variant 2: http://olevel.sourceforge.net/papers/9702/9702_s12_qp_22.pdf
Variant 3: http://olevel.sourceforge.net/papers/9702/9702_s12_qp_23.pdf

THNX A TONNN!!

 

[raamish]

Qp : http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_qp_2.pdf
M.s: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_ms_1 2 3 4 5 6.pdf

I have an issue in qs 2aiii) The mark scheme is saying that power output will be greater because work would be done against friction but isnt that going to be subtracted from the power output of the car so that the output can be calculated? Also how do we do 3bi)

 

[raamish]

question paper: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s04_qp_2.pdf
marking scheme: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s04_ms.pdf
please help me with question 2 (b).

Intensity is directly proportional to square of A(A2) so it has double the intensity so it will have 4 times of amplitude. THe phase difference is 180 so the waves are in antiphase so draw the waves opposite each other so that they form like a stationary wave pattern.........................i think

 

[Kirabo Takirambudde]

please help with part (iii)

 

[Kumkum]

Intensity is directly proportional to square of A(A2) so it has double the intensity so it will have 4 times of amplitude. THe phase difference is 180 so the waves are in antiphase so draw the waves opposite each other so that they form like a stationary wave pattern.........................i think

thnx!!

 

[Minato112]

THNX A TONNN!!

No prob!

 

[raamish]

No prob!

hey can u answer my questions plzz

 

[Minato112]

hey can u answer my questions plzz

U mean this one?

Qp : http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_qp_2.pdf
M.s: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_ms_1 2 3 4 5 6.pdf

I have an issue in qs 2aiii) The mark scheme is saying that power output will be greater because work would be done against friction but isnt that going to be subtracted from the power output of the car so that the output can be calculated? Also how do we do 3bi)

 

[mrnt3250]

Please explain this to me.
9702/02/M/J/04
(Paper 2 - M/J 04)
Question 3 - Part b) ii)

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s04_qp_2.pdf
http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s04_ms_2.pdf

Thanks in advance.

 

[champ-student]

Please explain this to me.
9702/02/M/J/04
(Paper 2 - M/J 04)
Question 3 - Part b) ii)

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s04_qp_2.pdf
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s04_ms_2.pdf

Thanks in advance.

may b line is not on the points????????/
well i m junior so dont know mch bout it.......sorry

 

[Minato112]

Qp : http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_qp_2.pdf
M.s: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_ms_1 2 3 4 5 6.pdf

I have an issue in qs 2aiii) The mark scheme is saying that power output will be greater because work would be done against friction but isnt that going to be subtracted from the power output of the car so that the output can be calculated? Also how do we do 3bi)

The explanation is:
The power output is larger since additional work must be done against friction. The case here, since the speed is constantly increasing, the air resistance force also increases. Thus the case will have to output more power to do so.

The values you calculated for the part 2 (b) (ii) are the power output assuming no additional work is done.

3 b) (i) For the increase in length, U find by how much the pointer moved down.
(6.5/360) * 2 * "pie" * 1.5
= 0.17 cm.

(ii) Increase in strain = Extension / Length
= 0.17 /[ (2.5 * 100) ] --------> Convert to cm
= 6.80 * 10^-4

Hope it helps.

 

[Asheeta]

please help with part (iii)

Using power= (V^2/R)
R = (230^2)/1000
therefore R = 52.9 ohm
effective R = [(1/52.9) + (1/52.9) + (1/52.9)]^(-1)
power = (v^2/R)
so power = (230^2)/ effective R
and the ans should be 3KW

Hoped it helped and could you just give me the answers for the above 2 questions as well. Thanks in advance.