• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Physics: Post your doubts here!

Messages
169
Reaction score
117
Points
38
Re: Physics Help here! Stuck somewhere?? Ask here! :)

Can anyone tell me what should i learn for pressure in lquids for As level and please give me the detailed explanation of viscosity in liquids asap !!! thanks
If you are attending oct/nov exam for physics go throught the syllabus and study according to learning outcomes

besides you can check wether you should study pressure and upthrust !
 

Attachments

  • physics_syllabus 2012.pdf
    829 KB · Views: 2
Messages
373
Reaction score
33
Points
28
Qp : http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_qp_2.pdf
M.s: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_ms_1 2 3 4 5 6.pdf

I have an issue in qs 2aiii) The mark scheme is saying that power output will be greater because work would be done against friction but isnt that going to be subtracted from the power output of the car so that the output can be calculated? Also how do we do 3bi)
 
Messages
373
Reaction score
33
Points
28

Intensity is directly proportional to square of A(A2) so it has double the intensity so it will have 4 times of amplitude. THe phase difference is 180 so the waves are in antiphase so draw the waves opposite each other so that they form like a stationary wave pattern.........................i think :unsure:
 
Messages
948
Reaction score
5,542
Points
503
Intensity is directly proportional to square of A(A2) so it has double the intensity so it will have 4 times of amplitude. THe phase difference is 180 so the waves are in antiphase so draw the waves opposite each other so that they form like a stationary wave pattern.........................i think :unsure:
thnx!!
 
Messages
6,232
Reaction score
5,003
Points
573
hey can u answer my questions plzz :)
U mean this one?
Qp : http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_qp_2.pdf
M.s: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_ms_1 2 3 4 5 6.pdf

I have an issue in qs 2aiii) The mark scheme is saying that power output will be greater because work would be done against friction but isnt that going to be subtracted from the power output of the car so that the output can be calculated? Also how do we do 3bi)
 
Messages
1,634
Reaction score
4,971
Points
273
Messages
6,232
Reaction score
5,003
Points
573
Qp : http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_qp_2.pdf
M.s: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_ms_1 2 3 4 5 6.pdf

I have an issue in qs 2aiii) The mark scheme is saying that power output will be greater because work would be done against friction but isnt that going to be subtracted from the power output of the car so that the output can be calculated? Also how do we do 3bi)

The explanation is:
The power output is larger since additional work must be done against friction. The case here, since the speed is constantly increasing, the air resistance force also increases. Thus the case will have to output more power to do so.

The values you calculated for the part 2 (b) (ii) are the power output assuming no additional work is done.

3 b) (i) For the increase in length, U find by how much the pointer moved down.
(6.5/360) * 2 * "pie" * 1.5
= 0.17 cm.

(ii) Increase in strain = Extension / Length
= 0.17 /[ (2.5 * 100) ] --------> Convert to cm
= 6.80 * 10^-4

Hope it helps.
 
Messages
39
Reaction score
24
Points
18
please help with part (iii)

Using power= (V^2/R)
R = (230^2)/1000
therefore R = 52.9 ohm
effective R = [(1/52.9) + (1/52.9) + (1/52.9)]^(-1)
power = (v^2/R)
so power = (230^2)/ effective R
and the ans should be 3KW

Hoped it helped and could you just give me the answers for the above 2 questions as well. Thanks in advance.
 
Top