Physics: Post your doubts here!

[Bloodlines]

calculte the difference of energy....
this energy would be lost due to the frictional efeects....now calcate the force by Workdone=force*d

 

[Tabi Sheikh]

calculte the difference of energy....
this energy would be lost due to the frictional efeects....now calcate the force by Workdone=force*d

never thought about it that way...... good work..........

 

[Jspake]

that skier one question..
firstly calculate G.P.E....at the top, which the skier possess...by the relation E.P=mgh=750*300...
now calculate K.E at the bottom....K.e=0.5*75*40^2

calculte the difference of energy....
this energy would be lost due to the frictional efeects....now calcate the force by Workdone=force*d

Thanks man

 

[aleezay]

Please share the link for the examiner report for November 2011's paper if any one has it asap. Thanks in advance

 

[salvatore]

hope this will help you.
View attachment 19405

Thanks a lot

 

[Tabi Sheikh]

Thanks a lot

ur welcomed

 

[A*(a*)]

ur welcomed

Anyone with Physics specimen of paper2 or paper1?

 

[Tabi Sheikh]

Anyone with Physics specimen of paper2 or paper1?

Sorry bro don't have.......

 

[magnesium]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w06_qp_1.pdf
SOMEONE HELP!!!!!!!!!!!!!!
Q12, 4, 25

 

[Minato112]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w06_qp_1.pdf
SOMEONE HELP!!!!!!!!!!!!!!
Q12

Using Principle of linear momentum,

Sum of momentum before = Sum of momentum after

Initially, they are both at rest => v = 0
Therefore the momentum before is 0

After the cannon ball is fired, the cannon ball moves forward a the cannon experiences a recoil velocity, that is, it moves backward.

Therefore, sum of momentum after,
= (1000 * - 5) + (10 * v)

Sum of momentum before = Sum of momentum after

0 = (1000 * - 5) + (10 * v)
0 = -5000 + 10v
10v = 5000
v = 500 m/s

Note : -5 is used since the cannon is experiencing a recoil force in the opposite direction.

Hope it helps.

 

[salvatore]

http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_s09_qp_2.pdf
No. 2 (d)

How do you solve the question? Please help!

 

[Tabi Sheikh]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s09_qp_2.pdf
No. 2 (d)

How do you solve the question? Please help!

you will use the conservation of momentum i.e. final momentum - initial momentum =0

 

[Bloodlines]

salvatore..variant 21 or 22.?

 

[salvatore]

salvatore..variant 21 or 22.?

Variant 21.. please show me the working of no. 2 (d)

 

[daw1996]

does any one have November 2012 pastpapers for (As physics)

 

[Bloodlines]

yar...firslty u have to calculate the velocity of ball S..
now apply elastic collision cases...if any of them suits here then it would be a elastic collision or otherwise inelastic..
for elastic..relatve speed of approach=speed of separation..
speed of approach=4(velocity of ball before collision)+0(velovity of ball S).
speed of separation=0.8(fromgraph)+speed of ball S after the collision)....(dont use the negative sign with value of velocity from the graph,as negative sign only sows a change in direction)...

if spped of approach turns out to be equal to speed of separation..then elastic..otherwise inelastic

 

[sma786]

Umm, i want to know which papers i'm going to give for physics for my AS..
i mean in the timetable its phy paper 21,31,41,32,51,11 :\

 

[daw1996]

Umm, i want to know which papers i'm going to give for physics for my AS..
i mean in the timetable its phy paper 21,31,41,32,51,11 :\

you'll be taking papers 11, 21, and ( 31, or 32)

 

[salvatore]

you will use the conservation of momentum i.e. final momentum - initial momentum =0

yar...firslty u have to calculate the velocity of ball S..
now apply elastic collision cases...if any of them suits here then it would be a elastic collision or otherwise inelastic..
for elastic..relatve speed of approach=speed of separation..
speed of approach=4(velocity of ball before collision)+0(velovity of ball S).
speed of separation=0.8(fromgraph)+speed of ball S after the collision)....(dont use the negative sign with value of velocity from the graph,as negative sign only sows a change in direction)...

if spped of approach turns out to be equal to speed of separation..then elastic..otherwise inelastic

Thanks!

 

[Yousif Mukkhtar]

Guys, does anyone have the marking scheme for
9702_s02_ms_1.pdf