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Yes, yes. You did.Did i get the correct answer??
can sum1 plz ans ASAPhow do you find the time interval using the callibrated time base of a cro?
count the 1cm boxes for the wave and multiply with the caliberation. be careful to convert the time where needed.can sum1 plz ans ASAP
maybe bcuz the question says "when it JUST conducts" then if it is working then it would record the voltage of the passing of current and we can't record it for the instant it begins to conduct... by reversing the diode it blocks the current after it reaches the diode and that current is measured.View attachment 20886
In this question, logically the answer I think (and also my teacher said this) that it would be A because the cell needs to be varied (in order to increase voltage, current and thus allow the diode to conduct) so B and C are wrong. Then it has to be A because D isn't forward-biased i.e. current travels from positive terminal and is blocked by the diode, so it HAS to be A but the mark scheme says that the answer is D for some reason, can anyone please care to explain?
I don't understand, what do you mean by 'if it's working then it would record the voltage of the passing of current...'? Can you explain further please?maybe bcuz the question says "when it JUST conducts" then if it is working then it would record the voltage of the passing of current and we can't record it for the instant it begins to conduct... by reversing the diode it blocks the current after it reaches the diode and that current is measured.
Do you mean that in D, the current would be blocked except when the emf is high enough, at THAT point the current will start passing and the reading on the voltmeter will give the initial voltage which we're looking for? Whereas in A the current will keep passing anyway because of the position of the diode so the voltage reading won't be that of the diode when it begins to conduct. Is that what you meant? If so then I got it!maybe bcuz the question says "when it JUST conducts" then if it is working then it would record the voltage of the passing of current and we can't record it for the instant it begins to conduct... by reversing the diode it blocks the current after it reaches the diode and that current is measured.
thanxcount the 1cm boxes for the wave and multiply with the caliberation. be careful to convert the time where needed.
if u don't get it then ask again and i'll do what i can to help gud luk
what i mean to say is that the required potential value is of the instant the current reaches the diode. if we use a working diode circuit then we woun't be able to spot that one value as with the passage of current through the diode the value will change. however when current is blocked by the diode then for an instant the current does reach the diode and that instant is recorded, regardless of the fact whether the current keeps flowing through or is blocked.Do you mean that in D, the current would be blocked except when the emf is high enough, at THAT point the current will start passing and the reading on the voltmeter will give the initial voltage which we're looking for? Whereas in A the current will keep passing anyway because of the position of the diode so the voltage reading won't be that of the diode when it begins to conduct. Is that what you meant? If so then I got it!
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