- Messages
- 176
- Reaction score
- 148
- Points
- 53
snowbrood
the distance of block from the level of head of the man is 18m and when to level the head with the block man travels 9m upwards and block 9m downwards.
tension acts towards the pulley and the weight acts opposite to tension i.e downwards.
force acting in the direction of acceleration is considered more in magnitude than the force in opposite direction
for the man
T-80g=80a equation 1
120g-T=120a equation2
adding both equations we get
40g=200a
a=0.2g (given g as 10ms^-2)
a=2ms^-2
v^2=2as (as initial velocity of both the objects is zero )
v^2=2*2*9
v^2=36
v=6ms^-1
i understood qs 24 very well ....but still haven't got an idea about this qs 12...plsss...label the words "a"...etc...and write eqs first ....like mg=ma ...what ever is the equation.... i am sorry for the inconvinience but i am a medical student ....and mathematics has always been my enemy .... ...lol
the distance of block from the level of head of the man is 18m and when to level the head with the block man travels 9m upwards and block 9m downwards.
tension acts towards the pulley and the weight acts opposite to tension i.e downwards.
force acting in the direction of acceleration is considered more in magnitude than the force in opposite direction
for the man
T-80g=80a equation 1
120g-T=120a equation2
adding both equations we get
40g=200a
a=0.2g (given g as 10ms^-2)
a=2ms^-2
v^2=2as (as initial velocity of both the objects is zero )
v^2=2*2*9
v^2=36
v=6ms^-1
i understood qs 24 very well ....but still haven't got an idea about this qs 12...plsss...label the words "a"...etc...and write eqs first ....like mg=ma ...what ever is the equation.... i am sorry for the inconvinience but i am a medical student ....and mathematics has always been my enemy .... ...lol