- Messages
- 1,660
- Reaction score
- 11,026
- Points
- 523
cn any1 help me in mj12 qp12-30
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
u need to find the average of current as it says the current is reduced uniformly.so current is 60A and t is 8.so q=it and 480CThe current in a component is reduced uniformly from 100 mA to 20 mA over a period of 8.0 s.
What is the charge that flows during this time?
A 160 mC B 320 mC C 480 mC D 640 mC
ya it helpedthe uncertainties should be to atleast one significant figure and the number of significant figures for this part will depend on all the previous uncertainties. if u put them to one sig. figure then u should do the same for this one as well. i think it should be 8 and 7.
hope i've helped
Thanks!for the sound at m to be zero that means destructive interference.so for destructive interference the path difference must be be a odd number of multiple wavelength
and for the second conditon if the amplitudes are same so there will be destructive interference as the two waves cancel out each other
so for the first 1 it would be the path difference must be be a odd number of multiple wavelength and 2 nd one amplitude amplitude of both the waves are same at m.
b)v=f lambda.so u put these values and u get 2 value of l(convert the unit in cm).that means the minima would be within the range.now find the path differnce.find the length of s2m by pythagoras theorem which is 128 cm.so the path difference for s2m-s1m is 28 cm.now apply the formula of path difference for destructive interference
28=(n+.5)l put the value of n to o,1,2,3,4.now u will get 2 values which are within the range.so 2 minima would be detected
Why is the answer C:-
View attachment 22713
M/J 2012 P11 Qs 12 ....concept pls ???..........
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_11.pdf
no need to think of the other things.they are saying they are using the same material.so the young modulus should be same as the 1st 1.so ans ic cWhy is the answer C:-
View attachment 22713
thanks..buddy!First See the the two 30N forces (They are a couple since they are parallel and in opposite direction with a distance between them.)
Torque is produced by a couple. Since they are in opposite directions .. there will be a torque .. so resultant torque is non-zero.
Now look at the 20N forces .. since they are NOT in opposite directions .. They are NOT forming a couple.. so there won't be torque. since both are in the same direction and the forces are not cancelling each other out .. the resultant force will be non-zero.
To understand this one .. forget that those 30N forces are even there.. What will happen if you pull a tyre from the top and bottom via a rope in the same direction.. the tyre will move .. meaning the resultant force is non-zero.
Answer: D
i Think B :SView attachment 22749
i can solve this but i dont get one thing is the force exerted on X by Y or force exerted by Y on X the same?
you can look at this as a pully attached with 2 mass, the man is the lighter object while the barrel is heavier objectMay/June 2012 P11 Q 12....Concept with complete solution plsss!!!!
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s12_qp_11.pdf
why is the answer of question number 40 'c'. Can anyone please explain. http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s07_qp_1.pdf
thanks manThat's a hard one.. My teacher had talked about this question before..
F=Vq/d=ma
so a Vq/md
let's take Li as an example, q for Li is 3 but m for Li is 7 (7 nucleons) , so a= 3/7 ( I ignore V and d cuz it's the same)
and after you work out the acceleration for other elements in this way, you will find Li has the smallest acceleration..
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now