Physics: Post your doubts here!

[snowbrood]

http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_w04_qp_4.pdf

can anyone solve Q4c(i)

 

[snowbrood]

http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_w04_qp_4.pdf

can anyone solve Q4c(i)

 

[salvatore]

Could anyone please help me with no. 1 (c & d) of the following paper?
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s12_qp_41.pdf

Thanks

 

[SIstudy]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s04_qp_2.pdf
can sum1 explain Q3 (B) (i)

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s05_qp_2.pdf
Q1 (b) & (d)

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w05_qp_2.pdf
Q3 (d) - i don't understand where is the resultant?

http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_s06_qp_2.pdf
Q1 (b)

 

[Hemdon]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s04_qp_2.pdf
can sum1 explain Q3 (B) (i)

Hi, the formula for gradient is : (y2-y1)/(x2-x1).....take two coordinates but keep in mind that the x-axis is in SQUARE form, so u need to square any 2 points. substitute and ull get the answer.

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s05_qp_2.pdf
Q1 (b) & (d)

For b the answer is 1, cause this is the standard value

 

[Jaspreet Dhaliwal]

Hi guys, could somebody help with questions, 6 , 13 , 14 , 17!! , 21, 24, 27, 28 , 32,
thanks would be very much appreciated

 

[daredevil]

Hi guys, could somebody help with questions, 6 , 13 , 14 , 17!! , 21, 24, 27, 28 , 32,
thanks would be very much appreciated

ummm link??

 

[Jaspreet Dhaliwal]

http://olevel.sourceforge.net/papers/9702/9702_s13_qp_11.pdf

ummm link??

sorry hahaha!

 

[daredevil]

http://olevel.sourceforge.net/papers/9702/9702_s13_qp_11.pdf
sorry hahaha!

np
send the link so maybe i will know how to solve ur questions and can help u

 

[Hong94]

physics paper4 mayjune 2009 question 1c(ii),3(i)2,3(ii),6C,11b(iii) i dont understand the answer sheet help please

 

[queen of the legend]

physics paper4 mayjune 2009 question 1c(ii),3(i)2,3(ii),6C,11b(iii) i dont understand the answer sheet help please

link please ?!

 

[Hong94]

link please ?!

http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_s09_qp_4.pdf
http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_s09_ms_4.pdf

the first link is the question, 2nd link is the answer, thankyou!

 

[Hong94]

link please ?!

http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_s09_qp_4.pdf
http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_s09_ms_4.pdf

the first link is the question, 2nd link is the answer, thankyou!

 

[Yousif Mukkhtar]

Guys, I need some help in this paper:
http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_w08_qp_4.pdf
Q 1 b)i)

 

[Yousuf Ykr]

can anyone solve paper 12 of Oct/Nov of 2012? i gat only problems wid 14, 18, 30 and 37

 

[danyaljamil]

Guys, I need some help in this paper:
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w08_qp_4.pdf
Q 1 b)i)

you need to know for this question that the earth is not exactly spherical but is an ellipsoid and hence its radius varies and is greater at the equator than at the poles hence the weight of any object and the normal reaction at the equator is different than at the poles
hope this helped

 

[adibshamsuddin]

9702_w09_qp_22.pdf . I need help with this question, 5 (b) . Why the phase difference is 180 degree. Please, little help would be very appreciated.

 

[6Astarstudent]

9702_w09_qp_22.pdf . I need help with this question, 5 (b) . Why the phase difference is 180 degree. Please, little help would be very appreciated.

judging from the fact that you asnwered part A, you know its a sinusoidal stationary wave and X has same amplitude as Y. But at any instant they are moving in opposite direction so they're 180 degrees out of phase.

 

[adibshamsuddin]

9702_w05_qp_2.pdf Can anyone help me with 7 (b) (ii) 1. Why is the pd 2.70? galvanometer reading would be zero not voltmeter?

 

[6Astarstudent]

9702_w05_qp_2.pdf Can anyone help me with 7 (b) (ii) 1. Why is the pd 2.70? galvanometer reading would be zero not voltmeter?

pd is 2.7 because V = V(total) x resistance (thermistor) / resistance (total) = 4.5 x 1800 / (1200+1800) = 2.7 this is a potential divider.
and it doesnt matter if its a galvanometer or voltmeter or not, because the potential is equal so potential difference is 0.