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Q12: we'll take this problem in terms of the forces acting on the barrel and the manCan anybody plz help me wid QUESTION 12 of this paper the answer is A......and also wid QUeSTION 15 whose answer is D....
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s12_qp_11.pdf
for the barrel: the force due to the barrel - the tension in the rope(T) = ma (because the barrel move's down, the force due to the barrel is greater than the tension)
(120*10) - T = 120a (we dont know the acceleration of the man and the barrel)
for the man: the tension (T) - the force due to the man = ma
T - (80*a) = 80a
find the value of a using simultaneous equations, which is 2 ms^-2
using v^2=u^2 + 2as
find the final velocity of the man at 9 m, taking u as 0 ms^-1
Q15 in order to keep the column from falling, the reaction force must move to the right.