- Messages
- 253
- Reaction score
- 1,195
- Points
- 153
ok its for studying chp is long closed lets not start it back agnthose words were offcourse not in yr limits
xpc is for studying not for this nonsense talk !!!
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
ok its for studying chp is long closed lets not start it back agnthose words were offcourse not in yr limits
xpc is for studying not for this nonsense talk !!!
lol there sure r lots of inspectors hereI hope you notice I am not into replying another Nazi dude Musab100
ok it ends here.Lets just end it, but you are no one to judge and decide whats the meaning behind my simple sentences too
from a diff worldswell, this kind of physics is awesome
it ends but i guess more thn hers ur words seemed more inappropriate no matter how much anger but for a girl it was simply too wrong....ok it ends here.
Yes i am no one, but your word selection was inappropriate, I would say.
wha? 0.ofrom a diff worlds
it ends but i guess more thn hers ur words seemed more inappropriate no matter how much anger but for a girl it was simply too wrong....
now, can we just end up all that here?Okay
I really am not encouraging this argument but really, you need to update your dictionary of inappropriate words.. ***amd***
for the 1st step the formula ok is understood then u make pout the subject then wht has to be done i dont get then how to get it plz elaborately explain the first stepformulas u will have to use..
attenuation=10 x log(P in/P out)
signal to noise ratio=10 x log (P out/P noise)
attenuation per uni length=total att/total lenth
do as follow
1 find power out......using secong formula.. 30=10 x log(p out/6.5x10-6) so p out=6.5x10-3W
2.find attenuation using formula 1 att=1o x log(26x10-3/6.5x10-3) so attenuation=6.02dB
3 finally find length using formula 3 length= 6.02/0.2=30 km
link plzphysics paper 4 may/june 2003 1c. plz can someone help me out. i dont understand the calculation. thanks
https://fbcdn-sphotos-h-a.akamaihd...._=1394792318_16dcac96b5bc8233430f3b7be709b4a5solve plz sum1 solve my doubt test 2moro
link plz
There was absolutely no reason for you to have argued with someone publicly in a formal thread over such a petty thing.Excuse Me. In your limits please.
You should not have said this. And many other things.My best guess is he is your tweedledum, so I am not into teen drama.
Honestly, if there is anyone who is not in his/her limits, it's you. Using a language other than English in a proper thread, and that too an insulting one, is not allowed at all. So, you better watch what you are doing before telling others what to do and what not to.manhus shakal ki bai sharam aurat!
I understand and I apologize to you for arguing in a formal threadThere was absolutely no reason for you to have argued with someone publicly over such a petty thing.
You should not have said this. And many other things.
Honestly, if there is anyone who is not in his/her limits, it's you. Using a language other than English in a proper thread, and that too an insulting one, is not allowed at all.
And next time when you people find a post offensive, simply report it, and we will handle the rest. Do not act as backseat moderators.
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now