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Physics: Post your doubts here!

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forgive me i didn't sleep last night and i don't know what i am saying. i confused it with the question in which the distance was found for work done.
I don't know why i multiplied distance.
charge per point = Q, charge pass per round=4, round per second=f
A=charge/time=charge.frequency while charge being 4Q
giving us 4Qf as final answer.
 
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forgive me i didn't sleep last night and i don't know what i am saying. i confused it with the question in which the distance was found for work done.
I don't know why i multiplied distance.
charge per point = Q, charge pass per round=4, round per second=f
A=charge/time=charge.frequency while charge being 4Q
giving us 4Qf as final answer.
got it . thanks for the help bro . please help with other questions when you are ok :)
 
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People,
Tell me how to find the minimum pd here:

A cell of e.m.f. 2.0 V and negligible internal resistance is connected to a variable resistor
R and a metal wire,
The wire is 900 mm long and has an area of cross-section of 1.3 × 10–7 m2. The
resistance of the wire is 3.4 Ω.The resistance of R may be varied between 0 and 1500 Ω. What is the minimum pd?
according to markscheme- ans=4.5 x 10^-3
its of 9702/21/O/N/11 please help! :)
 
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Can someone please explain why the answer to q37 of p1 mj2007 is C? I would really appreciate it if someone replies before Thursday as I have to appear for an exam on Thursday!
 
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I think it would be helpful if you read the attached files once. you can skip the half-life part
few things not included are,
The rate of decay is proportional to number of particles present

dN/dt ∝ N

dN/dt = -λN

part (b) asks for probality of rate of decay

part (c)(i) asks for the inittial activity and it can easily be found by the formula
part (c)(ii)
If A = λN

Then, A0 = λN0
find N0
then using
N0/NA =M/Mr

Where NA = Avogadro’s constant

Find M
 

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