Physics: Post your doubts here!

[Student12]

wss the ans of 15?

B

 

[ashcull14]

B is the answer ?
If yes, then use the formula :
0.5 * F * extension
0.5 * 17 * (30 * 10 ^-2) = 2.6

im sry its A

 

[Thought blocker]

Thought blocker or anyone else. http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s10_qp_11.pdf11 , 15 , 17

Sorry Zarah for the delay
11)


15)
Power = Force * velocity
Power = (1000 + 1000*10) * 0.5
Power = 11000 * 0.5
Power = 5500 W = 5.5 kW

17)
P = ρgh
(110000 - 100000) = 1020*9.81*h
h ≈ 1.00 mm

 

[ashcull14]

B

P=F*v
total force to lift the crane=(9.8*1000)+1000=10800N
10800*0.5=5400=5.4kW

 

[ashcull14]

Sorry Zarah for the delay
11)
View attachment 45245

15)
Power = Force * velocity
Power = (1000 + 1000*10) * 0.5
Power = 11000 * 0.5
Power = 5500 W = 5.5 kW

17)
P = ρgh
(110000 - 100000) = 1020*9.81*h
h ≈ 1.00 mm

u ddnt solve my que..

 

[Thought blocker]

View attachment 45243 ok in this how do we do that counting the boxes method....or the area one plx explain

 

[Thought blocker]

u ddnt solve my que..

Calm down... I am doing my preparations along with helping you all... After all I am a human!

 

[ashcull14]

View attachment 45246

thnks..

 

[ashcull14]

Calm down... I am doing my preparations along with helping you all... After all I am a human!

man i was kidding..im sorry if u minded it

 

[Thought blocker]

man i was kidding..im sorry if u minded it

I didn't took it seriously..
I neva take things seriously..

 

[abdulrahmanmirxa]

please help

 

[Thought blocker]

please help

What type of help you need ?

 

[abdulrahmanmirxa]

view the attachment? in the upper post

 

[Thought blocker]

please help

view the attachment? in the upper post

18)
power output P=IV
23 x 320 =7360 W
power input Power=energy/time
so P=mgh/t
and m/t is= 200 kgs-1
so 200 x 9.81 x 8 =15696 W
output/input x 100
7360/15696=0.468
nd 0.498 x 1ooo =46.8
so answer is D

 

[crazytaylorfanXD]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s11_qp_12.pdf

Q 32 , ,33

 

[ashcull14]

hey where am i going wrong?
i did it like this:- net emf=3-1.2=1.8V
V1=9/27*1.8=0.6V
0.6/9=0.067...y is my ans wrong?

 

[ashcull14]

i thin

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_12.pdf

Q 32 , ,33

k in q32...as l is doubled the cross sec area will be halved as well as it is an elastic material so R=2*2=4

 

[Thought blocker]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_12.pdf

Q 32 , ,33

32)
V = P / I = C

33)

i thin

k in q32...as l is doubled the cross sec area will be halved as well as it is an elastic material so R=2*2=4

 

[Thought blocker]

View attachment 45251 hey where am i going wrong?
i did it like this:- net emf=3-1.2=1.8V
V1=9/27*1.8=0.6V
0.6/9=0.067...y is my ans wrong?

Question ?

 

[abdulrahmanmirxa]

thnk

18)
power output P=IV
23 x 320 =7360 W
power input Power=energy/time
so P=mgh/t
and m/t is= 200 kgs-1
so 200 x 9.81 x 8 =15696 W
output/input x 100
7360/15696=0.468
nd 0.498 x 1ooo =46.8
so answer is D

thnx