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Have you changed the units to m for the diameters and length?
Yes, it's a square wave.... Best of luck for your exam today
Thanks.
Yes I can't make the graph
switch-it enables the aerial for transmission and receipt of signal
sir, the next part of the questionHave you changed the units to m for the diameters and length?
Btw its my way:
R=p*l/A
7.5=p*(1750/1000)/(phi*(0.5*0.38*10^-3)^2)
7.5*phi*(0.5*0.38*10^-3)^2=1.75p
p=7.5*phi*(0.5*0.38*10^-3)^2/1.75
p=4.8604*10^-7 ohm m.-->4.86*10^-7 ohm m
Hope this helps!
Thanks a lot.Bless you
So the lowest frequency is always at lambda/4? What about the fundamental frequency? Confused
Are u on facebook? Any Group / page of yours.
Thanks
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