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Lol if u want to tag ppl add "@" nd thn write their nameHow come Physicist didnt see my question?i dont noe how to tag people
....but pls answer my doubt
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w13_qp_21.pdf
Q2(a)...why isnt it 240m?
Thnks...can u solve my question?Lol if u want to tag ppl add "@" nd thn write their name![]()
s=ut+o.5at^2PLZ SOMEONE HELP WITH Q3 part (b)(ii)
s=ut+o.5at^2
u will be 0 as it says moves from REST
s=0.5at^2
rearange the equation to make a the subject
2*s/t^2=a
and the grainet is y/x that means d/t^2
s is distance and so is d
so gradient=s/t^2
2*gradient=a
I hope it helped![]()
Haha yeahDo you visit Sir Faisal ?because of the serial no "11" (i also have this worksheets with me)
btw here is the solution.
View attachment 49969
230V - 225V = 5VQp: http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w07_qp_2.pdf
Ms: http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w07_ms_2.pdf
Q6 b.
According to the mark-scheme the potential difference across the cable is 5V.
How????
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