Physics: Post your doubts here!

[mehria]

thank you soo much!

btw.. there's another thing, you got sometime?

my pleasure (^_^)
yup

 

[..sacrifice4Revenge..]

1 http://prntscr.com/75zebj
2- http://prntscr.com/75zdy9

can you do this question,
and also explain this a bit. I kind of have missed this topic altogether.
like if for side AB force, we use length of BC, why's that.
and if the coil was rotated and now is perpendicular, how will we calculate force on AB now.

mehria

 

[TheJDOG]

is this how i should do it ?

Yes

 

[farhan980]

Could someone just give me a quick explanation with tips on how I should find the area under a graph when I'm asked to do so? Do I count the squares? Then what? Thank you

Yes

thank you very much . Oh and for the area under the graph, yes u have to count the number of squares and multiply by the area of one square .

 

[..sacrifice4Revenge..]

1eV=1.6x10^-19 J
Why in some calculations is 1.6x10^-13J used?:S

 

[farhan980]

1eV=1.6x10^-19 J
Why in some calculations is 1.6x10^-13J used?:S

1eV=1.6x10^-19
1MeV=(1.6x10^-19)x(10^6)=1.6x10^-13

 

[Mahnoorfatima]

https://docs.google.com/viewerng/vi...wp-content/uploads/2012/11/9702_s12_qp_33.pdf
Question 1 part e. Can someone PLEASE explain how to find units ?????

 

[mehria]

1 http://prntscr.com/75zebj
2- http://prntscr.com/75zdy9

can you do this question,
and also explain this a bit. I kind of have missed this topic altogether.
like if for side AB force, we use length of BC, why's that.
and if the coil was rotated and now is perpendicular, how will we calculate force on AB now.

mehria

cn u post the ms as well?

 

[Komail Sabba']

http://maxpapers.com/wp-content/uploads/2012/11/9702_w14_qp_41.pdf

Question 5bii please.

 

[..sacrifice4Revenge..]

1 http://prntscr.com/75zebj
2- http://prntscr.com/75zdy9

can you do this question,
and also explain this a bit. I kind of have missed this topic altogether.
like if for side AB force, we use length of BC, why's that.
and if the coil was rotated and now is perpendicular, how will we calculate force on AB now.

mehria

Physicist can you please explain :|

mehria ms has used BC length for Force on AB
BC force is zero

 

[..sacrifice4Revenge..]

Pg 2
http://www.directupload.net/file/d/3990/w2ndknja_jpg.htm

Last part
Sorry for the bad angle

 

[..sacrifice4Revenge..]

http://imageshack.us/photo/my-images/540/3MXWb3.jpg

Is this correct? Except for the arrows..

 

[Debonny1]

Help? It's a non-inverting circuit btw with a gain of 10

 

[Shadow]

Can anybody provide me notes of telecommunication? I really suck at this topic And i'll be losing about 10 marks straight if i don't study it all. Anybody?
Also i want some notes on A2 core topics of line spectrum and temperature. It would be great if anybody would help me with this.

 

[TheJDOG]

Pg 2
http://www.directupload.net/file/d/3990/w2ndknja_jpg.htm

Last part
Sorry for the bad angle

We know that alpha( the intensity reflection coefficient ) is also = Ir/I
We need Ir
We got alpha in first part 0.33. From second part, I2=Ie^-ux
But since it's received back at the surface, it travelled twice the thickness, so it's 2x now.
So Ir= apha(I2)=0.33(0.39^2)(I)
This is why we square the fraction in part two.

 

[TheJDOG]

http://imageshack.us/photo/my-images/540/3MXWb3.jpg

Is this correct? Except for the arrows..

It is correct, since E=hc/lambda
The larger lambda, the less energy.

 

[..sacrifice4Revenge..]

Thanks alot Jdog!

 

[buckle_crackk]

Apply 2as=v^2-u^2
a is -g, v is 0 and u is vsinα.
Insert these values to get C.

thank you

 

[redd]

http://maxpapers.com/wp-content/uploads/2012/11/9702_s12_qp_42.pdf
Can anyone help with this Q6b) part. Why isn't the ans 1.6x10^-19

 

[Debonny1]

from which paper is this?

Nov 13/43