• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Physics: Post your doubts here!

Messages
1,229
Reaction score
740
Points
123
Sorry. Read All XZ as YZ. I was talking about the Flat area.

Distance YZ is constant.
If speed is high then YZ is covered quickly so t is less.
If speed is low (after rebound inelastic) YZ is covered in more time.

You must also compare area under vt graph. YZ is constant so area must remain constant.
you mean the shaded areas should be equal , right?
 

Attachments

  • Screen Shot 2015-06-09 at 8-1.06.30 PM.png
    Screen Shot 2015-06-09 at 8-1.06.30 PM.png
    41.9 KB · Views: 4
Messages
1,229
Reaction score
740
Points
123
The area between is the thermal energy dissipated. For a rubber, when it is extended they say that there is no permanent extension, however there will be heat exerted. The shaded area is the net work done and the area under the graph is the work recovered
Sorry but I don't get you.. can u shade for me the respective areas please :)
 
Messages
1,318
Reaction score
1,374
Points
173
upload_2015-6-9_21-28-43-png.54930

How and why D?
 
Messages
1,318
Reaction score
1,374
Points
173
The question is asking for Power. The first 2 answers give KE which is wrong. Its is D because you have to take into account the diff in mass. C just considers M1.
But then why do you need to consider the difference in mass? Won't you add the masses to get the total power? :S
 
Messages
1,318
Reaction score
1,374
Points
173
Volume = 2000 * 10 = 20000
Mass = 20000 * 1.3 = 26000
KE = 0.5 * 26000 * 10^2 = 1300J
efficiency is 50% so answer is 650KW


It is projectile motion, so the path is parabolic.
But it won't form a circle? Like the parabolic path is not part of any circle?
 
Top