thank you so, so much!!u = 1.66 x 10^-27
Mass of hellium is 4u = 4 x 1.66 x 10^-27
Like 100km = 100000m.
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
thank you so, so much!!u = 1.66 x 10^-27
Mass of hellium is 4u = 4 x 1.66 x 10^-27
Like 100km = 100000m.
The work done is basically the area under the graph ... And its a triangle so the formula works that way.Hey can anyone tell me that why do we use average force for strain energy i.e 1/2×F×e2
.....i mean isn't the extension produced by the full force rather than half the force (average force)....pls help me asap...thanks in advance ✊
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s11_qp_23.pdf
question 5 part c part iv
MS-(iv) horizontal line through central section of wave ?
I know what a horizontal line is. I don't get why.View attachment 58954
0.25T corresponds to a quarter cycle. So the new position will be as shown by the red line.
Lol.I know what a horizontal line is. I don't get why.
Yes,thank you for taking the time!Lol.
View attachment 58955
consider the point X. the blue line + green line + orange line + purple line = one cycle.
0.25 = quarter cycle.
so quarter cycle = blue line only.
if you do the same for all the other points on the wave, you'll see that after quarter cycle all the points will lie on the red line.
I hope i'm successful this time
View attachment 58997
why will the change in potential energy and the change in kinetic energy be equal??
Which part exactly do you not get?View attachment 58957
HELLO ANYONE??????????????????????????
Well I got it.View attachment 59007View attachment 59008View attachment 59009
b(ii), d(i)(ii) someone please explain it to me.. Thanks.
Conservation of energy. Total energy of an isolated system remains same (all forms in which energy is lost will be gained in other forms).
Here, there are only two energies that we need to consider, i.e, the kinetic energy and electric potential energy ... so loss in one equals the gain in other.
Oh sorry, I thought you didn't get only the energy part.thnx.. but can you pls help with the calculation part??
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now