Physics: Post your doubts here!

[Thelastmoment]

opps i meant Q 15 I knew this one it quite obvious. Thanku fr helping me Can u try 9,37,15?

Q37- Theory -Kirchoff's rule One and Two
Hope this helps
The rest I think Farjad is correct

 

[Thelastmoment]

does anyone know where to get the physics may/june 2017 paper 41. i know it's not yet uploaded but i was hoping if anyone of u knew how to get the paper

I don't know if that's possible.. although try this site justpastpapers.com it usually releases the papers 24h after the exam is conducted.

Lemme see if I can help.

 

[SohaibButt]

It's D need explanation

 

[Thelastmoment]

It's D need explanation

When a beta particle is emitted from the nucleus the nucleus has one more proton and one less neutron.And we know that an alpha makes it even lower..
So, A & B no way then to make sure it's the minimum reduction we choose D.
Because, 2 betas would remove more than one beta which btw is obvious ...

 

[SohaibButt]

When a beta particle is emitted from the nucleus the nucleus has one more proton and one less neutron.And we know that an alpha makes it even lower..
So, A & B no way then to make sure it's the minimum reduction we choose D.
Because, 2 betas would remove more than one beta which btw is obvious ...

Oh damn y didn't i focused thanks a lot!

 

[Zenn99]

Can someone pls tell me how to get the ans for Q13 in FEB/MARCH 2017 PHY MCQ paper?

 

[Zenn99]

the paper is here, can someone pls tell me how to get the ans for Q13 AND Q4

 

[amina1300]

the paper is here, can someone pls tell me how to get the ans for Q13 AND Q4

Q4:T=1/f 1/50000 and divide this f by 2. This makes 1 complete wavelength in 2 divisions and hence you get C as the answer.

 

[Aishayasin]

Question 6 Answeris B

 

[amina1300]

View attachment 62292 Question 6 Answeris B

Vertically:
s=ut + 0.5at^2
2=0+10*t^2
t= 0.32
horizontally:
s=ut+0.5at^2
a is 0
6/0.632 = v Answer is b

 

[Aishayasin]

Vertically:
s=ut + 0.5at^2
2=0+10*t^2
t= 0.32
horizontally:
s=ut+0.5at^2
a is 0
6/0.632 = v Answer is b

Can u explain it step by step .Thanks

 

[Aishayasin]

ANSWER IS B

 

[amina1300]

Can u explain it step by step .Thanks

Ok so the cyclist is moving in two dimensions - both horizontally and vertically. Since these two components of motion are independent of each other, two distinctly separate sets of equations are needed - one for the cyclist's horizontal motion and one for its vertical motion.

We take Vertical Motion 1st because we know that for a free-falling object acceleration is g and hence we calculate the time taken for it to fall.
This time is the same for the horizontal component to reach its end point so while for the Horizontal motion we take the distance mentioned as 6m and divide it by the time(a=0) and we get the answer. (s=ut) Note: I took g as 10ms-1

 

[amina1300]

View attachment 62295

ANSWER IS B

Horizontally:
The horizontal velocity remains same 4ms-1
Vertically:
v=u+at Note : acceleration is negative. as object is falling.
v=8+((-1.62)*9)= -6.58

Resultant final velocity:
sqrt(ans^2+4^2 ) = 7.7 ms^-1


Anymore questions

 

[Thelastmoment]

Q33 Needs an explanation. Answer is A.

 

[amina1300]

Q33 Needs an explanation. Answer is A.

R= pL/A and Ohms Law V=IR hence the thickest conductor has the least resistance so the smallest Voltage drop across the thickest conductor.A is answer. The potential drop with distance is represented by grad of graph so the value of the grad drop should be the smallest for the thickest conductor Since thre is a potential drop gad is -ve.

 

[Thelastmoment]

R= pL/A and Ohms Law V=IR hence the thickest conductor has the least resistance so the smallest Voltage drop across the thickest conductor.A is answer. The potential drop with distance is represented by grad of graph so the value of the grad drop should be the smallest for the thickest conductor Since thre is a potential drop gad is -ve.

Thanks a lot.

 

[Holmes]

Help !

 

[Thelastmoment]

Thanks a lot.

 

[Thelastmoment]

View attachment 62308

Help !

Hope it helps