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Physics: Post your doubts here!

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que no 5 please!! i do get the part that the value is accurate..but why isnt it precise?
 

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que 9 explaination please ..I went for option B ..but the answer is D
 

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que 9 explaination please ..I went for option B ..but the answer is D
I think the total kinetic energy of the girl remains constant.Because no external forces act except for the weight and the jumping action(which in turn creates an upward force greater than the weight ( so girl moves up). Therefore,
Resultant is constant.
But kinetic energy is affected by velocity which has direction.so when girl moves up the velocity becomes (+) and when she falls (-) and at the top point zero.

Hope this helps <3 <3 :LOL::LOL:
 

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The answer in the marking scheme is C, please point the mistake in my method; from which I got the answer A.
And also, what is the correct method for solving this question?
 

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The answer in the marking scheme is C, please point the mistake in my method; from which I got the answer A.
And also, what is the correct method for solving this question?
I=A^2
Intensity for wave 1 is given which is equal to amplitude (2*10^-2)^2
Amplitude for wave 2 is (3*10^-2)^2. Find the intensity of wave 2 by cross multiplying and the answer you'll get is C.
 
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The answer in the marking scheme is C, please point the mistake in my method; from which I got the answer A.
And also, what is the correct method for solving this question?
Under what conditions do you suggest that the time taken is equal in both waves?
 
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que 9 explaination please ..I went for option B ..but the answer is D
While she jumps and she is in the air, her velocity is decreasing uniformly (as acceleration is = -9.81) and is positive till her velocity is zero. Then she stays in mid air MOMENTARILY with velocity zero and falls with constant acceleration of 9.81 ms-1 in the OPPOSITE DIRECTION. Then as she lands on the trampoline and her velocity IMMEDIATELY CHANGES DIRECTION TO POSITIVE, and this repeats:

2 main important points:

1. acceleration AND deceleration is CONSTANT ( THUS NO CURVES, JUST STRAIGHT LINE GRAPH)
2. The line goes straight up cuz velocity changes direction immediately when she lands and is about to jump up again

HOPE THAT HELPS:D:D:D:D
 
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While she jumps and she is in the air, her velocity is decreasing uniformly (as acceleration is = -9.81) and is positive till her velocity is zero. Then she stays in mid air MOMENTARILY with velocity zero and falls with constant acceleration of 9.81 ms-1 in the OPPOSITE DIRECTION. Then as she lands on the trampoline and her velocity IMMEDIATELY CHANGES DIRECTION TO POSITIVE, and this repeats:

2 main important points:

1. acceleration AND deceleration is CONSTANT ( THUS NO CURVES, JUST STRAIGHT LINE GRAPH)
2. The line goes straight up cuz velocity changes direction immediately when she lands and is about to jump up again

HOPE THAT HELPS:D:D:D:D
THANKYOUUU!!
 
Messages
59
Reaction score
18
Points
8
I think the total kinetic energy of the girl remains constant.Because no external forces act except for the weight and the jumping action(which in turn creates an upward force greater than the weight ( so girl moves up). Therefore,
Resultant is constant.
But kinetic energy is affected by velocity which has direction.so when girl moves up the velocity becomes (+) and when she falls (-) and at the top point zero.

Hope this helps <3 <3 :LOL::LOL:
THANKYOU!!
 
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