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Post your AS-Level Mathematics (P1 and M1) doubts here.

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Hello can someone please explain to me how to solve Q5 ii , I found teta but I don't know the next step
Cosx = -2/3
so, cos inverse -2/3 gives you 131.8
now you got your one theta, hence; theta + 70 = 131.8 ---> theta = 61.8
so, you get theta as 131.8 and 61.8 .

Other than this,

360 - 131.8 = 228.2 as one theta
so, theta + 70 = 228.2 ---> theta = 158.2
so, you get theta as 228.2 and 158.2.

Hence, Both (theta = 131.8 and 61.8) and (theta = 228.2 and 158.2) are correct, you can write any of 'em.
Good luck (y)
 
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Cosx = -2/3
so, cos inverse -2/3 gives you 131.8
now you got your one theta, hence; theta + 70 = 131.8 ---> theta = 61.8
so, you get theta as 131.8 and 61.8 .

Other than this,

360 - 131.8 = 228.2 as one theta
so, theta + 70 = 228.2 ---> theta = 158.2
so, you get theta as 228.2 and 158.2.

Hence, Both (theta = 131.8 and 61.8) and (theta = 228.2 and 158.2) are correct, you can write any of 'em.
Good luck (y)
Thanks sooooooo much and good luck to you to ;)
 
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Hey there, I'm sorry for any inconvenience I create dropping this bomb of a message because all of you lot are probably driven into some P1/M1 problem, and I'm just butting in.

HOWEVER.
I have serious problems in M1, Nauzobillah.
I get so damn confused when to use a certain equation for a certain situation for work done/energy problems.

Could anyone be kind enough to neatly write down all the formulae for every possible scenario regarding this? Examples: when starting from rest down an inclined plane, what's the work done against friction?

Also, can somebody please clarify the difference between "work done" and the "work done against friction"? It's all pig Latin.

Warm regards,
Oishee
 
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