Your answer should be of same decimal place as that of uncertainty.if you ve taken your coordinates to 3 sf then should nt your gradient be to 3 or 4 sf?? do correct me if i m wrong
and v kind of you
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Your answer should be of same decimal place as that of uncertainty.if you ve taken your coordinates to 3 sf then should nt your gradient be to 3 or 4 sf?? do correct me if i m wrong
and v kind of you
Hey did you get the diagram?
I got 13% :O
I did it this way: check image.View attachment 28394View attachment 28395
My gradient is -7000+-745
THANKYOUU
June 2003 P5 Question 2
Procedure : 1 . The experiment is set up as shown. Radium source is used since it has a very long half life. As the experiment is performed in a short time interval, there will be no change in count-rate due to decreasing activity of the source.
2. Initially, the radium source is removed and background countrate is measured (Cb) at a given p.d
3.The radium source is placed at a fixed distance 'd' from the aluminium sheet and the countrate is measured. Several values of the countrates are measured and the average value is calculated so as to minimise the effect of the random nature of emission. The true countrate, C, is obtained by subtracting the background countrate(Cb) from the measured countrate.
4. The source is removed, the p.d is changed and recorded. The new background countrate is measures and recorded. The source is then placed at the same distance from the G.M tube and the new countrate is measured and recorded.
5. Aluminium sheet is used as an absorber of alpha and beta particles. Thus, the countrates recorded are due to gamma rays only.
Safety precautions :
1. The source is handled using a pair of tongs.
2. Te source is stored in a thick lead lined box when not in use.
3. Care should be taken no to look directly into the source.
June 2003 P5 Question 2
Why cant we use Bismuth??
R = R0 e^pnx
ln(R/R0)=pnx
ln0.1=11300 * ur value in d part * x
Use the gradient of best fit to calculate y-intercept and then use worst acceptable gradient to calculate y-intercept.The difference of these y-intercepts is the error of the constant.
Nobody is genius.We are all learners.
can u mention any question in which we have to calculate this..[/quo@te]
magnesium thats ok sis.. i got that
log(x)=3Also, I'd need help with logarithmic equations, exponential functions, exponential and power law variations! Any help will be appreciated!
diagram is available in this thread
Hey, i'm really sorry I couldn't post it earlier, I was kinda pressed for time on other matters.
Sorry if the diagram isn't good enough (It looks bad, but in this time, it's the best I could do - sorry!)
View attachment 28405
Good Luck for all your exams!
are we suppose to do such old p.papers? i did from 2007 to 2012
Hey, i'm really sorry I couldn't post it earlier, I was kinda pressed for time on other matters.
Sorry if the diagram isn't good enough (It looks bad, but in this time, it's the best I could do - sorry!)
View attachment 28405
Good Luck for all your exams!
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