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Solved physics Paper 5??

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now see, for the error bars lets say the error is +- 0.5 and the point is 22 for the x axis
then the error bar must be from >> 21.5 and 22.5
how do you make the error bar now, for this you must see what is the value of one square on the x-axis. Lets assume one box on the x axis is 0.05. Which means and error of 0.5 on each side will cover 10 boxes on the x axis. To draw the error bar you will draw a horizontal line (because error is for a value on the x-axis) which will be 10 boxes behind 22 and 10 boxes ahead of it!
If the point 22 was for the y axis, then the error bar would be a vertical line of 10 boxes above and below 22.

hope this can help :)
Thank you so much (y)
and can you plz help me
to find uncertainty of v^2 (CIE A level October November 2012 Variant 3 )?
i really need help in finding uncertainty especially which include these kinds of products and division.
:)
 
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now see, for the error bars lets say the error is +- 0.5 and the point is 22 for the x axis
then the error bar must be from >> 21.5 and 22.5
how do you make the error bar now, for this you must see what is the value of one square on the x-axis. Lets assume one box on the x axis is 0.05. Which means and error of 0.5 on each side will cover 10 boxes on the x axis. To draw the error bar you will draw a horizontal line (because error is for a value on the x-axis) which will be 10 boxes behind 22 and 10 boxes ahead of it!
If the point 22 was for the y axis, then the error bar would be a vertical line of 10 boxes above and below 22.

hope this can help :)
but sometimes they tell to join all the error bar peaks. how can it be done?
 
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Please tell me whether this diagram is correct....I dont know how to position the microphone...Please help

N09/51 Q1
Attached Files:

 
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hey guys in qs 2 ofn09/51 in calculating gradient im calculating gradient by using these values= 2.795-2.988/2.519-2.47. So should i round these values to 3 sig figures or should i round the answer of gradient that comes to 3 s.f. If i round these values before calculating the gradient the value of gradient is changed a little. WHat is the procedure for this can anybody tell me. And in d part the error for h and g should be carried from gradient and y intercept right. for e.g if error of intercept 0.05 then for g it is also 0.05?
 
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hey guys in qs 2 ofn09/51 in calculating gradient im calculating gradient by using these values= 2.795-2.988/2.519-2.47. So should i round these values to 3 sig figures or should i round the answer of gradient that comes to 3 s.f. If i round these values before calculating the gradient the value of gradient is changed a little. WHat is the procedure for this can anybody tell me. And in d part the error for h and g should be carried from gradient and y intercept right. for e.g if error of intercept 0.05 then for g it is also 0.05?
Find the gradient first and then round it. For part d, h is the same as gradient. For g its not the same. log g = y intercept. so to find g u have to inverse log or 10^ ur y intercept value. Then to find error u use the same way of log. Find inverse log highest value of y intercept - inverse log y intercept :D
 
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My problem is I don't know how to describe experiments or how to draw an appropriate diagram !!:cry:
Dont worry ! You can score a minimum of 5-10 marks by just writing basic lines. Just write as much as u know about the given experiment. The variables, graph drawing, safety precautions and anything related to your experiments :D
 
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in j10/52 the answer to 2d is coming 987+- 24.1 This absolute uncertainty is very strange to me. Can anybody check their answers to this part and confirm that the uncertainty i have calculated is correct or not . to calculate uncertainty i used formula= g from best fit line grad- g from worst fit line gradient to calculate the absolute uncertainty or error. Can anybody confirm plz

and can anybody also tell what is their percentage uncertainty coming. Mine is 4.44% I am having trouble taking it out
 
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Soldier313
Can you help me with the question i posted above?:)

Hey sis sorry, apparently i don't get your tags :confused:
Anyways about the diagram for that paper, i was stuck with it too, i'm not quite certain, but i think a tuning fork would be a better option right ?
Anyways i hope someone can elaborate further...
geek101 littlecloud11
We need some clarification with the on/09 qp 51 diagram

And while you are at it, could you please also look at on/07 qn 1 too? I don't understand how to draw the diagram :/
Would really appreciate if you guys could upload your diagrams for these questions :)
Thank you :)
 
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in j10/52 the answer to 2d is coming 987+- 24.1 This absolute uncertainty is very strange to me. Can anybody check their answers to this part and confirm that the uncertainty i have calculated is correct or not . to calculate uncertainty i used formula= g from best fit line grad- g from worst fit line gradient to calculate the absolute uncertainty or error. Can anybody confirm plz

and can anybody also tell what is their percentage uncertainty coming. Mine is 4.44% I am having trouble taking it out



i got an error of 19.5, i think what you are doing is correct
i did it this way though :
[ (error in gradient)/ (gradient of best fit) ] x g

and my percentage error value is 3.99 %
I'd prefer if someone else confirms with this though
 
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i got an error of 19.5, i think what you are doing is correct
i did it this way though :
[ (error in gradient)/ (gradient of best fit) ] x g

and my percentage error value is 3.99 %
I'd prefer if someone else confirms with this though

i mean that i calculated percentage uncertainty like this: [error/value of g + 2*0.01(error of t)/value of t]* 100
my answer came : [24.1/987 + 0.01*2/1] * 100
=2%+2.44%=4.44%

is this method correct?
and i also want to know if a value is like 3 sig figures should the error be 3 sign figures as well or should it have same decimal places as the value. e.g 2.41+-0.19 or 2.41+-0.20.
 
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and one another question i always calculate my absolute uncertainty from the percentage uncertainty in questions such as qs 2b of n12/53.
so how do we calculate the absolute uncertainty directly when values both having absolute uncertainties are being divided, multiplied or added. Like values of t/s and l/cm
. In this question they are being divided so how will we calculate the absolute uncertainty of them. I know its v2 so the uncertainty will be multiplied by 2 afterwards.
 
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how do I add a picture here? I've taken a snapshot of a question that's confusing me but i'm not sure how to upload it here? !
 
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