3Do u remember how much marks were allocated for each question?
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
3Do u remember how much marks were allocated for each question?
Do u remember how much marks were allocated for each question?
what are u expecting in maths A*?4, 3, 3
0 1 2The paper was manageable
What did you get the values for the probability distribution table?
Lol.. those are the values of X.0 1 2
idrLol.. those are the values of X.
What did you get the probabilities for each?
if it was theni can go back to hoping it was an awesome rocking paperQ6 iii) it was 8!x9P4 not 12!-(9!x4!)
Total trees 15.
Hibiscus:4, Oleander: 2 J-something: 9
(i) selection of 12 trees where there has to be a minimum of two of each kind.
A: 2O, 2H, 8J = 2C2*4C2*9C8 = 54
2O,3H, 7J = 2C2*4C3*9C7 = 144
2O, 4H, 6J =2C2* 4C4*9C6= 84
total = 54+144+ 84 =282
(ii) The company picks 6J, 4H and 2O. How can they be arranged if the trees of the same type are are kept together.
A: 3!*4!*6!*2!= 207360
(iii) Arrange the 12 trees so that the hibiscus plants are not together.
A 12! -(9!*4!)
syed1995
saifookhan
if it was theni can go back to hoping it was an awesome rocking paper
this or 8!*9*8*7*6 same thingI kinda have a doubt in the last part.. I think you did it wrong. I remember a similar question came in the papers previously.. where it said no two women are together...
we did something like ..
_*_*_*_*_*_*_*_*_ where * is one of the other trees.. and the _ is where the Hill billy would go..
I did it as 8!*4!*9C4 = 1.22*10^8 Answer (3sf) (Which can otherwise be written as 8!*9P4)
Another set consists of 6 plastic mugs each of a different design and 3 china mugs each of a
different design. Find in how many ways these 9 mugs can be arranged in a row if the china
mugs are all separated from each other.
littlecloud11
Check http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_61.pdf
Question 6 part ii...
Solve this for me..
Another set consists of 6 plastic mugs each of a different design and 3 china mugs each of a
different design. Find in how many ways these 9 mugs can be arranged in a row if the china
mugs are all separated from each other.
Using your method first. and then check the MS.
dude i can tell mine cam total at 0.998 what could i have doneYo if you can tell me the toffees / chocolates in each bag.. I can calculate it for you right here right now.
yes i did the sameQ6 iii) it was 8!x9P4 not 12!-(9!x4!)
I got 0.25, 0.175 and 0.575 as the probabilities.. but I kinda feel I've messed up somewhere. Yeah, I don't think they would penalise you since the format wasn't mentioned in the question.one of them was 4/27 I think.. I don't remember them sorry.. I had a chemistry practical today.. so maths is totally out of my mind... My total sum of probabilities was coming as 1 so I did that one right.
Btw how did your practical go? Do you remember yours.. if you post them maybe I will be able to help better.. I wrote them all in fraction.. They won't penalize me would they?
I got 0.25, 0.175 and 0.575 as the probabilities.. but I kinda feel I've messed up somewhere. Yeah, I don't think they would penalise you since the format wasn't mentioned in the question.
You're talking about AS chemistry practical right? I did that on 14th May! It was pretty lengthy but not hard
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now