Stat v. 62

[AdeelRox]

It dpends on the gt bro but an a for sure

I have told you the minimum marks that I expect, I desperately want an A*

 

[pakiboy]

I have told you the minimum marks that I expect, I desperately want an A*

Me 2 lets hope we get it!

 

[daredevil]

littlecloud11 syed1995 MustafaMotani daredevil and others please post GT acording to you
mine is around 37 +-1

ummm... i think 34 ot 36

 

[Hassan Ali Abid]

tat was part c

i did that part with nCr /............ total were 12 and there were 5 chocolates ....so i took the probability of 0 choco,then 1 and so on .....dont know if i have done it correctly or not

 

[lionkill3r]

i did that part with nCr /............ total were 12 and there were 5 chocolates ....so i took the probability of 0 choco,then 1 and so on .....dont know if i have done it correctly or not

i never liked nCr method

 

[Hassan Ali Abid]

i never liked nCr method

but was there any possibility to do the question by that method ???????? cz i think i have lost all marks in q7.......may be some working marks will be awarded

 

[S.Mashaal.N]

i did that part with nCr /............ total were 12 and there were 5 chocolates ....so i took the probability of 0 choco,then 1 and so on .....dont know if i have done it correctly or not

me too!

 

[S.Mashaal.N]

they had men

How many of you considered the trees of a particular type identical. For example for part ii i said that no. of arrangements was 3! because the arrangements of the trees within each block is not important after all the hibiscus trees are not different. they are identical. If cie really wanted us to think that trees of a particular species are different then they are out of their minds. They could have given a better example which wasn't so confusing.....

tioned in the question dat each tree of a specie was different

 

[Mishaa]

GUYS I USED 96=np and 32= np(1-p) ! but still i calculated the value wrongly will i be awarded any marks ? p.s this is my only mistake i hope ! -_-

That's what happened to me too! Every step was perfect but the answer is fluctuating a tad. I'm hoping I'd get 2 out of 4 atleast, for finding np and npq AND setting the k/9 probabily.

 

[Hassan Ali Abid]

That's what happened to me too! Every step was perfect but the answer is fluctuating a tad. I'm hoping I'd get 2 out of 4 atleast, for finding np and npq AND setting the k/9 probabily.

when u got the value of n incorrect then how u got k correct

and what about that last question

 

[A star]

when u got the value of n incorrect then how u got k correct

and what about that last question

if u would have the courtousy to look in previous answers some one perhaps little cloud wrote them

 

[Mishaa]

when u got the value of n incorrect then how u got k correct

and what about that last question

I wish I knew, it's kind of funny.

Oh I messed up, I thought it was about toffees drawn from Ahmed's bag. I set the table for 0, 1, 2, 3,4 and 5. Got it right at the last moment, heh. Alhumdulillah! xD

 

[Hassan Ali Abid]

I wish I knew, it's kind of funny.

Oh I messed up, I thought it was about toffees drawn from Ahmed's bag. I set the table for 0, 1, 2, 3,4 and 5. Got it right at the last moment, heh. Alhumdulillah! xD

i also did the same .......

 

[Mishaa]

i also did the same .......

Did you get it right baad main?

 

[razahayat777]

anyone got the question paper?

 

[razahayat777]

does anyone of you remember the statement of last question part (i)?

 

[Hassan Ali Abid]

Did you get it right baad main?

nai ...i dont remember exactly that if i have done that part correctly ....but may be i will score some marks of working

 

[donorsolutions]

Y

Q6 iii) it was 8!x9P4 not 12!-(9!x4!)

Yes u are right. Because it said all the hibiscus trees had to be separated. If u calculated the arrangements for them to be together and subtracted it from total it would also involve those arrangements in which two hibiscus trees or three hibiscus tree is together.

 

[amnah]

Does anyone remember the outliers question? what'd you get for it + how'd you do it?

 

[Prof. MHA]

Total trees 15.
Hibiscus:4, Oleander: 2 J-something: 9

(i) selection of 12 trees where there has to be a minimum of two of each kind.
A: 2O, 2H, 8J = 2C2*4C2*9C8 = 54
2O,3H, 7J = 2C2*4C3*9C7 = 144
2O, 4H, 6J =2C2* 4C4*9C6= 84
total = 54+144+ 84 =282

(ii) The company picks 6J, 4H and 2O. How can they be arranged if the trees of the same type are are kept together.
A: 3!*4!*6!*2!= 207360

(iii) Arrange the 12 trees so that the hibiscus plants are not together.
A 12! -(9!*4!)

syed1995
saifookhan

In the last part didn't they mean that no two (or more) hibiscus plants could be together?