Statistics 1: Post Your Doubts Here

[Amy Bloom]

Khalifa & babycry thank you guys!

 

[momo_khan]

can any one help me with question 6 part 2 from ----> http://olevel.sourceforge.net/papers/9709/9709_s12_qp_61.pdf

question 2 from -----> http://olevel.sourceforge.net/papers/9709/9709_s12_qp_62.pdf

question 2 and question 6 part two from ----> http://olevel.sourceforge.net/papers/9709/9709_s12_qp_63.pdf

does anyone have some good notes for statistics ?

 

[Amy Bloom]

Help needed with:

 

[Amy Bloom]

momo_khan
can any one help me with question 6 part 2 from ----> http://olevel.sourceforge.net/papers/9709/9709_s12_qp_61.pdf

question 2 from -----> http://olevel.sourceforge.net/papers/9709/9709_s12_qp_62.pdf (Go to http://www.xtremepapers.com/community/threads/statistics-1-post-your-doubts-here.13281/page-3 - this question was answered by ladmireblue)

question 2 and question 6 part two from ----> http://olevel.sourceforge.net/papers/9709/9709_s12_qp_63.pdf

does anyone have some good notes for statistics ?

 

[babycry]

Help needed with:
View attachment 17822

by doing trial and error, a=1 since a can only be 1 or 2 since onle -1 and -2 are presnt.

4i. 5bowlers,5 batsmen 1 wicket keeper: 10c5*9c5*2c1
4 bowlers, 6 batsmen, 1 wicket keeper: 10c6*9c4*2c1
4 bowlers, 5 batsmen 2 wicket keep: 9c2*10c5*2c2

total is 148176

iii. since there is only 1 way of choosing 5 pens from 5 identical pens, you dont consider doing 5c5 etc.
so 5pen 4 diary 1 notebook: 10!/5!4!
4pen 4 diary 2 notebook: 10!/4!4!2!
5 pen 3 diary 2 notebook: 10!/5!3!2!

total is 6930. pm me or post here if u need any clarification

 

[momo_khan]

momo_khan
can any one help me with question 6 part 2 from ----> http://olevel.sourceforge.net/papers/9709/9709_s12_qp_61.pdf

question 2 from -----> http://olevel.sourceforge.net/papers/9709/9709_s12_qp_62.pdf (Go to http://www.xtremepapers.com/community/threads/statistics-1-post-your-doubts-here.13281/page-3 - this question was answered by ladmireblue)

question 2 and question 6 part two from ----> http://olevel.sourceforge.net/papers/9709/9709_s12_qp_63.pdf

does anyone have some good notes for statistics ?

thank you Amy Bloom

 

[Iadmireblue]

thank you Amy Bloom

Q6-part 2
Draw up a normal dist curve and you need to find the area before -1 and after one
Then find the probability which would be 0.3174,then multiply it by 1000 to get the number of feathers

http://olevel.sourceforge.net/papers/9709/9709_s12_qp_63.pdf
Q2 ii)
If you take a look at the formula booklet,you can see sqr root(x-Mean)^2/n = standard dev
Just solve

q6 ii)
34 cm to the nearest cm mean it could lie anywher betweer 33.5 to 34.5 draw up a normal dist curve and find the area inbetween these two points

Hope it helped
and good luck

 

[momo_khan]

Q6-part 2
Draw up a normal dist curve and you need to find the area before -1 and after one
Then find the probability which would be 0.3174,then multiply it by 1000 to get the number of feathers

http://olevel.sourceforge.net/papers/9709/9709_s12_qp_63.pdf
Q2 ii)
If you take a look at the formula booklet,you can see sqr root(x-Mean)^2/n = standard dev
Just solve

q6 ii)
34 cm to the nearest cm mean it could lie anywher betweer 33.5 to 34.5 draw up a normal dist curve and find the area inbetween these two points

Hope it helped
and good luck

jazakAllah khair thank you soooooooooooooooooooooooooo much !

 

[Amy Bloom]

by doing trial and error, a=1 since a can only be 1 or 2 since onle -1 and -2 are presnt. <-- What's the link with probability = 17/35?

4i. 5bowlers,5 batsmen 1 wicket keeper: 10c5*9c5*2c1
4 bowlers, 6 batsmen, 1 wicket keeper: 10c6*9c4*2c1
4 bowlers, 5 batsmen 2 wicket keep: 9c2*10c5*2c2

total is 148176

iii. since there is only 1 way of choosing 5 pens from 5 identical pens, you dont consider doing 5c5 etc.
so 5pen 4 diary 1 notebook: 10!/5!4!
4pen 4 diary 2 notebook: 10!/4!4!2!
5 pen 3 diary 2 notebook: 10!/5!3!2!

total is 6930. pm me or post here if u need any clarification

Thanks for all the explanations, except that the very first question (in green), which i don't get. can you give me some more clarifications on that please?

 

[Amy Bloom]

thank you Amy Bloom

Most welcome

 

[babycry]

Thanks for all the explanations, except that the very first question (in green), which i don't get. can you give me some more clarifications on that please?

ok think of it another way.. a can only be 1 or 2 right? since there is only -2 and -1. but since it says 2a, there is no -4 on the table so the only answer is a=1

 

[InnocentAngel]

Hey friends , i just wanted to know if we lose marks if we don't put the answer in 3 sf

 

[babycry]

Hey friends , i just wanted to know if we lose marks if we don't put the answer in 3 sf

i think u only get penalised once

 

[leadingguy]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_ms_63.pdf
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_63.pdf
qstn 3 part 3 for 1 mark how to find variance??

 

[Iadmireblue]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_ms_63.pdf
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_63.pdf
qstn 3 part 3 for 1 mark how to find variance??

Variance = npq=30*0.4*0.6

 

[Amy Bloom]

ok think of it another way.. a can only be 1 or 2 right? since there is only -2 and -1. but since it says 2a, there is no -4 on the table so the only answer is a=1

Okay but what's the link with 17/35?

 

[Amy Bloom]

Only (V)

 

[babycry]

add the probabilities between -2 and 1

 

[Amy Bloom]

add the probabilities between -2 and 1

Cool thanks!
I have posted a doubt above. can u help me in dat?

 

[yazan1995]

who is doing 62 tomorrow ?