- Messages
- 821
- Reaction score
- 231
- Points
- 53
62which variant??
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
62which variant??
You can find some Statistics Lectures here: http://www.khanacademy.org/math/statistics
Don't forget to check out the Probability Section too: http://www.khanacademy.org/math/probability
Please feel free to share tips and skills here.
Okay, to be honest, I have barely opened the book yet and I really need those marks to pass. Mechanics was hard, I lost 20 marks easily, and I left about 4 or 5 questions in P3, so I need to do my best in this paper. I only studied for P1 and P3 honestly..
Should I start by opening the book or by directly solving past papers? I need to achieve 30 marks or more (inshallah). The only things I have studied so far are measure of location and spread.
I need to study those still:
Normal Distribution
Binomial Distribution
Probability
Permutations and Combinations
So what are your suggestions? And I know, I did fail in maths this year.
Q6;(i) It is give that P(X<20)=0.1can someone plz solve and explain this question.
Q7;(i) P(answered correctly)=(0.7)+(0.2*0.95)
p=.8 q=.2 np=30*.8=24 npq=30*.8*.2=4.8can anyone help me with m/j 2011 question number 2....1st part
god bless u...plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz
no .... we ddont hav to minus from 1hey i want to ask u that if the z has a value of say 0.228 whose inverse cannot be found out from the table.228 ....thus in this case do we need to do 1-0.228 =0.772 from the value......that is something....???why bt
Q6;(i) It is give that P(X<20)=0.1
P(X>20)=0.9 which from the table is 1.282
P(X<20)=z of -1.282
z=-1.282
so (20-mean)/standard deviation=-1.282
(20-mean)/0.8=-1.282
From this we get mean=21.0(i.e 3 significant figures)
Q6;(ii) P(21.5<X<22.5)=P(X<22.5)-P(X<21.5)
=((22.5-21.03)/0.8)-((21.5-21.03)/.8)
=(1.8375)-(0.5875)
From the table
=0.967-0.7217
=0.2453
Now this the probability for success(i.e length between 21.5-22.5)
P(X<2)=P(1)+P(0)
=4C1(0.2453)^1(1-0.2453)^3+4C0(0.2453)^0(1-0.2453)^4
=0.746
Hope you understand this....
How did u get it...can u explain me againno .... we ddont hav to minus from 1
we hav to take ,228 value from inside the table i.e .5902
hopee u understood
hey how did u get 0.590p=.8 q=.2 np=30*.8=24 npq=30*.8*.2=4.8
P(X<25)
P(Z<24.5-24/sqrt4.8)=.228=.590
*sqrt=square root
*.590 from the table
same here can anyone plzz helpi don't understand when to choose the negative value of z.
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now