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question 7
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can somebody help me with thisheybro and can u plzzz tell me the steps in detail for this....i know its easy bt a silly mistake here maybe.....IMAGINE......PLZZ
View attachment 10543
can u give me the qs??WHY THERE IS NO CONTINUITY CORRECTION???
can u help me with this one........i gt that one cc someone told it is only when there is suitable approximationcan u give me the qs??
needs qs bro!can u help me with this one........i gt that one cc someone told it is only when there is suitable approximation
so was it just normal distribution kya??. or we had to convert binomial??can u help me with this one........i gt that one cc someone told it is only when there is suitable approximation
This! Someone help!!http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_62.pdf
In question 4(iv) shouldn't we be first finding out our class boundaries? The mark scheme directly used the values in the table for the histogram.
According to me the class boundaries should be:
-0.5≤x<19.5 19.5≤x<29.5 29.5≤x<39.5 39.5≤x<44.5 44.5≤x<49.5 49.5≤x<59.5 59.5≤x<69.5
The mark scheme specifically mentions a mark for 'correct bar widths starting at 20'.
Help?
WHY THERE IS NO CONTINUITY CORRECTION???
why it is being deducted by 0.5??WHY THERE IS NO CONTINUITY CORRECTION???
Assalamoalaikum wr wb!Can someone tell me how to improve my permutations and combination skills?
heybro and can u plzzz tell me the steps in detail for this....i know its easy bt a silly mistake here maybe.....IMAGINE......PLZZ
View attachment 10543
tHIS HAS REALLY MADE IT EASY!watch this video ...
this may help you to understand y we deduct .05
AFTER GETTING 225/900 THEN WHAT DO U DO?hmm for qs (i)
state that P(X>1002) = 1-P(X<1002)
you understand this step??
I have simply taken like inverse of original form
for LHS, we have also given the probability = 225/900
now simply do the solvings doing LHS=RHS
finally u'll obtain ans: 997 (hopefully)
qs (ii).....
do the solvings binomially.
p=225/900=0.25
n=3
so, P(X=2) ...solve it
do the binomial solutionAFTER GETTING 225/900 THEN WHAT DO U DO?
oHHH YA!!do the binomial solution
easy, isn't it??oHHH YA!!
i don't understand when to choose the negative value of z.
same here...even i am confused
can anybody explain it
it's easy.....same here can anyone plzz help
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