Can you please name some theory questions? And just questions, I'll sort out the answers myself.Thankk you
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Can you please name some theory questions? And just questions, I'll sort out the answers myself.Thankk you
Anytime and lol did you check out that pic??THankk youu
noo cant find it, Kamihus gave the answer thank youAnytime and lol did you check out that pic??
yeah there is on in this paper may-june 10 variant 62 Question 1Can you please name some theory questions? And just questions, I'll sort out the answers myself.
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w13_qp_61.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w13_ms_61.pdf
Q5 i why we subtract 0.08 from 1 and then putted a negative value to z ? anyone ?
they asked 8% of carrots are shorter than c cm. Find the value of c. so why they subtracted 0.08-1 ? can u explain pleaseView attachment 43497
here are the rules
The random variable Y takes the value 0 if thetwo values of X are the same. Otherwise the value of Y is the larger value of X minus the smaller value of Xhttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s12_qp_62.pdf
can anyone plz help me with ques 2, the distribution table i suck in maths and i don't know this
p(x<c)= 0.08they asked 8% of carrots are shorter than c cm. Find the value of c. so why they subtracted 0.08-1 ? can u explain please
ok thank u so much hope we all get the grades we wishp(x<c)= 0.08
p(z<((c-14.2)/3.6)=0.08
ϕ((c-14.2)/3.6)=0.08
BUT if you see the table you cant find 0.08 and so you have to do 0.08-1
and then the z value you get from 0.08-1 you will add a negative sigh to it
You know you are having an exam in less than 10 hours you should know this my dear
got something else you need help with i am free right nowok thank u so much hope we all get the grades we wish
do u have any notes or advise about combination and permutation ?got something else you need help with i am free right now
the only notes i have of S1do u have any notes or advise about combination and permutation ?
The random variable Y takes the value 0 if thetwo values of X are the same. Otherwise the value of Y is the larger value of X minus the smaller value of X
So it is 2 and 2 or 4 and 4 or 6 and 6
then y=0
now to make the table we know 0 is there for sure
then use the other information
if 2 and 4
then y=4-2 (bigger value - smaller value)
or it can be 6 and 2 there y=6-2=4
ALL the possible ways of getting y=0
2 and 2 -------> from the table above (o.5*0.5)
4 and 4 ------>(0.4*0.4)
6 and 6 ------->(0.1*0.1)
add all this up you will get 21/50
ALL the possible ways you can get y=2
2 and 4 -----> (0.5*0.4)
4 and 2 ------>(0.4*0.5)
6 and 4 ------>(0.1*0.4)
4 and 6 ------>(0.4*0.1)
add all this up you get 12/25
ALL the possible ways of getting y=4
6 and 2 ------->(0.1*0.5)
2 and 6--------->(0.5*0.1)
add this up and you get 2/20
now making the table y 0 2 4
p(Y=y) 21/50 12/25 2/20
Permutation (arrangements)do u have any notes or advise about combination and permutation ?
Good LuckGonna do my exam in a few hours!!! When I finish I'll give you on idea on how tough/easy the paper is!
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