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The Ultimate AS Physics Thread

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libra94 said:
7b....u use the equation d sinθ = λn
make sure all the units are in meters!!!
λ = 630 / 1000 000 000
n= 2
sinθ = (162 - 136) / 2
then find ur d, which is equal to 5.6*10^-6 m!!

Y Did U Do .. "sinθ = (162 - 136) / 2" :unknown:
 
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MHHaider707 said:
@libra94: hey, can you please help in O/N 07 P2 Q.4 (c)??

Plzzzzzzz
here, u subtract the area of the cylindrical rod by the area when the rod is under tensile stress
---->from the graph, the tensile stress is 9*10^8 Pa...this is when the rod has the smallest cross sectional area (due to necking)
stress= force / area
area= force/ stress
force = 1.9*10^3 N
stress = 9*10^8 Pa
so ur area will be 2.11* 10^-6 m^2

so (3.2*10^-6) - (2.11* 10^-6) = 1.2*10^-6m^2!!
 
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nealDSA said:
libra94 said:
7b....u use the equation d sinθ = λn
make sure all the units are in meters!!!
λ = 630 / 1000 000 000
n= 2
sinθ = (162 - 136) / 2
then find ur d, which is equal to 5.6*10^-6 m!!

Y Did U Do .. "sinθ = (162 - 136) / 2" :unknown:
cuz the angle taken must be between n=0 and n=2!!
 
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Another Question libra94

Thanx libra94
How to find the wavelength in Nov 03 Q4a

Thanx very much for your help once again
 
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libra94 said:
nealDSA said:
libra94 said:
7b....u use the equation d sinθ = λn
make sure all the units are in meters!!!
λ = 630 / 1000 000 000
n= 2
sinθ = (162 - 136) / 2
then find ur d, which is equal to 5.6*10^-6 m!!

Y Did U Do .. "sinθ = (162 - 136) / 2" :unknown:
cuz the angle taken must be between n=0 and n=2!!

Still :%) :unknown: :( >> Could U Pls Explain This In Detail !!
 
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Re: Another Question libra94

darkie123 said:
Thanx libra94
How to find the wavelength in Nov 03 Q4a

Thanx very much for your help once again
wavelength is the distance between 2 points on 2 successive waves
so we use fig 4.2 cuz the x-axis is the distance
so lets take 2 crests, and find the distance between then
u'll get 7.5 cm :)
 
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Sully17 said:
libra94 said:
@nealDSA...hope this helps :D
lol at the image
Do you devide by 2 because 2 is the order of spectrum or do you have to do that always?
:p making fun of my drawing? :p
u ALWAYS take the angle between n=0 and n=x (x can be 1,2,3,4,5,6......)
in this question n=2
by subtracting 162-132 we get 26' which is the angle between n=2 and n=2
we want the angle between n=2 and n=0 as i said before
now look at my image again, and stop making fun of it :p , u'll surely get it :)
 
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libra94 said:
Sully17 said:
libra94 said:
@nealDSA...hope this helps :D
lol at the image
Do you devide by 2 because 2 is the order of spectrum or do you have to do that always?
:p making fun of my drawing? :p
u ALWAYS take the angle between n=0 and n=x (x can be 1,2,3,4,5,6......)
in this question n=2
by subtracting 162-132 we get 26' which is the angle between n=2 and n=2
we want the angle between n=2 and n=0 as i said before
now look at my image again, and stop making fun of it :p , u'll surely get it :)

You didnt answer my question , did you devide 26 with 2 because n= 2?
 
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@sully17 NO!! the reason for this is my previous post..
@mueez, yeah i also want to know this one!! im getting the wrong answer :eek:
 
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Mueez said:
i got correct ans buh dnt knw why we cant use f=ke to get da value of k..
yeah i used that, and got wrong answer
which formula did u use then??
 
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