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Unit 2 Physics notes!!

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these are my guess! if im not correct, please correct me! :)

answer for Q4 is B
UV ray freq is higher(10^15) than that of visible light(10^14)!
according to equation E=hf, energy of UV is high!
so it is from energy level 4 to 1!

the answer for
Q5 is D!
the current in (L+M) will be = to N!
because (L+M) is parallel and N is in series!
so when M is removed,
some of the current will move from N to L!
for example, consider:
L = 2A
M = 2A
N = 4A
when M breaks,
L will gain 1A from N,
making L = 3A & N = 3A
so, this increases brightness of Lamp L and decreases brightness of Lamp N

The answers are correct and yeah I think the explanations makes sense now..okay thanks a lot for the explanation! :)
 
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Can someone explain june 2009 last qustn (c) part 2???

since they said R is directly proportional to l^2
then R=((2.51^2/2.5^2)*0.22)
then the answer you get - 0.22 because they want the increase in resistance...
so change in R is 1.76*10^-3
 
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In jan 2013,question no 15 ,two resistors are parallel thn y do we hve to add all resistance to get totall resistance?
 
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how to get frequency in question no 6 in jan 2013?
for that the answer is C
first convert 5ms to seconds by dividing it over 1000!
that is 0.005!
then multiply it by 4, because it have four squares for 1 wavelength!
that is 0.02!
then use F=1/T
so 1/0.02 is 50Hz
thats it! :)
 
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since they said R is directly proportional to l^2
then R=((2.51^2/2.5^2)*0.22)
then the answer you get - 0.22 because they want the increase in resistance...
so change in R is 1.76*10^-3

Oh..I see..thanks!! :)
 
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finallyyy the ppr is over.....so hw wzz the exam!!!!!!!!
i felt it was easyyy...just the last part of last q. n the polarization was somethingg confusinggg!!!!!
 
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