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Very tough mathematics questions

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EXPLAIN THESE QUESTIONS... PLEASE
1. If n ∈ N, solve the equation cosn x − sinn x = 1, for x ∈ R.

2. Let a, b, c ∈ R, a2+b2 6= 0 and L = {(x, y) ∈ Q×Q | ax+by = c}.
a) Can you find an example of (a, b, c) such that L = ∅ ?
b) Can you find an example of (a, b, c) such that L has a unique
element?
c) Prove that if L contains two elements, then L has infinitely
many.

3. Show that the set
A = {±1 ± 2 ± 3 ± ... ± 2006}
contains an even number of elements.

4. Find a polynomial P(X) of degree n , with real coefficients, satis-
fying
P(X)|P(X2 − 2007X + 2007).

5. A n× n matrix contains elements only +1 or −1, such that on any
row, on any column, and on the two diagonals of the matrix the
product of elements is −1. What are the possible values of n (n ∈ N)?
 
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Show me your attempt/working and I will point you into the correct direction.
 
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hamid ali..yeah these are very tough questions from NATIONAL MATH OLYMPIAD.i m also givin. aur saturday ko IST mein mera nmo ka exam hay......really tensed kyunki in mein se aik question bhi sae tarah se nae ata.....
 
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@MAvtknmJ....IF U KNW ANY QUESTION SOLUTION KINDLY SOLVE IT,,,,,,I WUD be very thankful......
 
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MAVtKnmJ said:
Show me your attempt/working and I will point you into the correct direction.

SIr! Please solve them if you have time. Atleast solve one or two of them. I have no clue about these questions. So help needed.
 
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Well I would have preferred an attempt from you guys before I solved these for you, oh well I hope you still learn something from my answers:

#3

It doesn't matter whether the number of elements in (1...2006) is even (the answer is yes, because 2006 is an even number). The point is that you have the negative numbers as well. So the number of elements in the set is double the number in (1....2006), so it must be even.

That is just the positive integers, and the negative integers (up to 2006).

ie, every positive integer and its negative partner

ie, every element can be paired with another one

Thus, it must be an even number of elements.

So the answer in a nutshell is:

2006 x 2 = 4012 , which is an even number. Shown!
 
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thanx for late late help.i had given NMO 2day it was gud....sum questions nwere tuf bt gave answers to all the questiions.there were 4 problems for 4 hours.......OMG
 
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