Physics: Post your doubts here!

[Hamnah Zahoor]

ah i was thinking the same and confused, thanks tho

You are welcome.

 

[Hisham Khan]

Private colleges are a waste!

I mean governement colleges ....
Private are as low as 15 lac per year lol

 

[khadijaimran]

this one please

 

[Kanekii]

this one please

Is it A?
Both electric field strength and weight of the object should act in opposite directions to balance vertical forces so that the particle could continue to move horizontally. So electric field strength can balance the weight acting downwards by applying a force upwards. If it was positioned upwards the particles negative charge would repel it downwards so its placed downwards to repel the negative charge upwards.

 

[Kanekii]

How?
Is the answer A for 24?

 

[hellodjfos;s'ff]

this one please

There needs to be a force pulling the particle up to balance out the weight of the particle. The particle will continue to move horizontally if the vertical forces are balanced.
If you look at A, the electric field is downwards meaning the positive terminal is up and since the particle would be negatively charged, the positive terminal will apply a force to pull the electron up. This fits the idea I presented at the start, so A is the answer.
For B, it will be the opposite of option A. So the force acting on the electron will be in the direction of the weight so the electron will be pulled down(incorrect since it won't be solely left to right).
For option C and D, the particle will be pulled down again so the particle won't move left to right only. So they're incorrect too

 

[khadijaimran]

Is it A?

yes

 

[khadijaimran]

There needs to be a force pulling the particle up to balance out the weight of the particle. The particle will continue to move horizontally if the vertical forces are balanced.
If you look at A, the electric field is downwards meaning the positive terminal is up and since the particle would be negatively charged, the positive terminal will apply a force to pull the electron up. This fits the idea I presented at the start, so A is the answer.
For B, it will be the opposite of option A. So the force acting on the electron will be in the direction of the weight so the electron will be pulled down(incorrect since it won't be solely left to right).
For option C and D, the particle will be pulled down again so the particle won't move left to right only. So they're incorrect too

thank you so much!!

 

[hellodjfos;s'ff]

View attachment 64122 How? View attachment 64123
Is the answer A for 24?

13: You can form a right angle triangle with 3,4 and 5N forces which give a resultant force of 0. I have shown this in the attached picture. The resultant of the forces, 3N and 4N is 5N. This resultant can be opposed by the other 5N force available, hence the final resultant force is zero.

 

[hellodjfos;s'ff]

thank you so much!!

Your most welcome

 

[A*****]

I mean governement colleges ....
Private are as low as 15 lac per year lol

Yeah that is what I was wondering

 

[Kanekii]

And yes, 24 is A. This is because if there are more layer of springs there will be more extension. Using F=kx, you would find that for the same load with a greater extension, the spring constant(k) decreases. Hence there will be less compression for the same load which is why A is the answer.

If more layers are there extension will decrease and spring constant will increase*

 

[hellodjfos;s'ff]

If more layers are there extension will decrease and spring constant will increase*

Actually, I don't think A is the answer. A will cause more extension... and they are asking for which option will not have a desired effect. Clearly A is a desired effect since there is more compression.

 

[Canttouchthis]

View attachment 64122 How? View attachment 64123
Is the answer A for 24?

It's B, I did this one today.

 

[Kanekii]

It's B, I did this one today.

Year?

 

[Canttouchthis]

helpaaa

 

[Canttouchthis]

Year?

may june 2011 paper 12

 

[Kanekii]

helpaaa

C?

 

[Canttouchthis]

C?

tahts what I thought too but it says a in the mark scheme

 

[Canttouchthis]

somebody solve thistoo plssss