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when drawing the hess cycle, do we always put the elements at the bottom?You'll have to make a Hess cycle for this question.
View attachment 64781
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when drawing the hess cycle, do we always put the elements at the bottom?You'll have to make a Hess cycle for this question.
View attachment 64781
Its really based on what you're dealing with, like what kind of reaction do you have and the kind of enthalpy you're trying to find.when drawing the hess cycle, do we always put the elements at the bottom?
B, As Ionic compounds conduct electricity in liquid state. Only 1 and 2 can be ionic compounds. As Y loses an electron to obtain stable electronic configuration and Both X and Z gain electron/s achieve stable electronic configuration.please help with thisView attachment 64782
Its B, As it has 4 different groups attached to the carbon atom.Which compound shows optical isomerism?
A.) 2-chloropropane B.)1,2-dichloropropane C.) 1,3-dichloropropane D.) 2,2-dicholoropropane
P1V1=P2V2View attachment 64787Idk how to arrive at an answer......the answer is A
Thanks!!P1V1=P2V2
(5*12)+(6*10)=P2*(5+10)
p2= 8
I did it and it was hard af. What about you?Who did qp 11 and how did you find it?
Sameee......i'm not even confident about my answersI did it and it was hard af. What about you?
I did it and it was hard af. What about you?
I did 12, and it was horrible as well.Sameee......i'm not even confident about my answers
In this case, the answer must be D.Q: Equal masses of barium carbonate and magnesium carbonate powders are mixed together. The mixture is then heated using a Bunsen burner flame until there is no further change. A gas is given off. Which statements are correct?
1) The residue left after heating reacts with aqueous hydrochloric acid to produce carbon dioxide.
2) The percentage decrease in mass after heating is 26% (to 2 significant figures).
3) The gas given off during heating relights a glowing splint.
1. The fact that some carbon dioxde is produced when the residue is treated with acid means that there is a carbonate present.
2. If 50% of the mixture is magnesium carbonate (relative mass = 84) and it decomposes to MgO (relative mass 40), then the 50% loses 44/84 x 100 % of its mass = 52.4%
so the mass loss of the 100% mixture = 26.2%( dont get this part)
How from 52.4 become 26.2?
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