sameeee i just drew some weird pipesI didnt know the nernst eqn part........that part just messed me up and the distialltion shit.......i didnt know wht to drw
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sameeee i just drew some weird pipesI didnt know the nernst eqn part........that part just messed me up and the distialltion shit.......i didnt know wht to drw
How did you do the last part of the last question?Good...How was yours?
But I think I messed up that table in Q2, still no worries it was of one mark only.
the percentage purity one?How did you do the last part of the last question?
Concentration of acid wasn't givenconcentration of nitric acid*0.25 dm^3 = no.of moles
then i calculated the mass then the purity.
it was to be taken from the graphConcentration of acid wasn't given
Yes it had to be taken from the graph and it was conc of Cu2+ which was 0.19it was to be taken from the graph
What was your answer?Yes it had to be taken from the graph and it was conc of Cu2+ which was 0.19
Mine was 60 something i think it was wrong.What was your answer?
What was your procedure?Mine was 60 something i think it was wrong.
Me too.........what did you get as your percentage yield?sameeee i just drew some weird pipes
Y-axis-Absorbance, X-axis-Conc of Cu2+What was your procedure?
And what was on the graph's other axis? I can't remember.
Now I remember,Y-axis-Absorbance, X-axis-Conc of Cu2+
I used n=CV with volume of 250*10^-3
Found Mass using molar ratios since and then divided this by the increase in mass which was given *100
Though i think this was wrong or i made some error
I just realised the stupid mistake that i made, i used the Mr of the whole compound instead of Cu.Now I remember,
we were suppose to calculate the percentage purity of copper
calculated conc. of copper = 0.19 mol dm^-3
volume 250 cm^-3
moles*Mr = 0.0475*63.5=3.0162g
purity = 3.0162/3.76 (if i remember the correct value)
80.2% was the answer
You still might get 1 or 2 mark for procedure.I just realised the stupid mistake that i made, i used the Mr of the whole compound instead of Cu.
Yes Hamnah Zahoor we had to take it from the graph but that was Cu²+ concenYes it had to be taken from the graph and it was conc of Cu2+ which was 0.19
Yes ...Sorry I just forgot.Yes Hamnah Zahoor we had to take it from the graph but that was Cu²+ concen
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