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Chemistry: Post your doubts here!

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View attachment 64779 can someone help with this? answer is B
In order for atoms to be in the same plane the bond angle must be 120 degrees
The central carbon atom in 1 and 2 has 3 B.P so the bond angle is 120 while in 3 the central carbon will also make a bond with hydrogen so it will have 4 B.P hence the bond angle will be 109.5 not 120.
 
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In order for atoms to be in the same plane the bond angle must be 120 degrees
The central carbon atom in 1 and 2 has 3 B.P so the bond angle is 120 while in 3 the central carbon will also make a bond with hydrogen so it will have 4 B.P hence the bond angle will be 109.5 not 120.
thank you
 
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In order for atoms to be in the same plane the bond angle must be 120 degrees
The central carbon atom in 1 and 2 has 3 B.P so the bond angle is 120 while in 3 the central carbon will also make a bond with hydrogen so it will have 4 B.P hence the bond angle will be 109.5 not 120.
sorry if this is a dumb question but what do u mean by B.P?
 
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Which compound shows optical isomerism?

A.) 2-chloropropane B.)1,2-dichloropropane C.) 1,3-dichloropropane D.) 2,2-dicholoropropane
 
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