Help Answer This Electromagnetism Physics P4 Question

[syazapion]

Q: Electrons are accelerated a potential difference of 220V. They then pass into a region of uniform magnetic flux of flux density 0.54mT.
The path of the electrons is normal to the magnetic field. Given that the charge on the electron is 1.6x10^(-19) C and it's mass is 9.1x10^(-31) Kg.
Calculate the speed of the accelerated electron.

A: 8.8x10^6 ms^(-1) <--- BUT HOW CAN YOU GET THIS ANSWER?? Please....Anyone. D8

 

[musa]

put 1/2mv^2=QV where
m is mass
v is speed
Q is charge
and V is voltage

 

[yasser37]

Electric energy = Kinetic Energy
Qe = 0.5 m v^2
v= root(2qw/m)


you'll get the answer

 

[syazapion]

OH COOOL! THANKS YOU GUYS!! Best of luck on you exams!

 

[TasdikMostofa]

which year question paper has this question?

 

[Thought blocker]

Wow, you replied to 2011 thread! hehe...

which year question paper has this question?

This exact question wasn't asked in any CAIE paper that I checked on the internet, but similar questions are usually asked in CAIE as well.
Change in KE = Vq is a typical formula that we use when electrons gain the speed due to potential difference (V)
If you are looking for the exact question, you can find it here on page 7:-

Magnetism For Physics Grade 12 | PDF | Electron | Magnetic Field

The document summarizes key concepts about magnetism: - Magnets can attract or repel other ferrous and non-ferrous materials. Iron can become magnetized when brought near a magnet through induced magnetism. - Materials are classified as ferrous if they contain iron or non-ferrous if they...

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