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oh got it now! thanks!
lol its funny but interestingI am not sure if u guys are in a way of studying like this but i find these easy to learn in the following hence providing you all with a way too learn Mobile Circuit.... Hope it helps..
Meri - microfone
Ami Foran - a.f amplifie
Ati - ADC
pitti - Parralell to Digital
marti - modulator-ossilator
aur - amplifier
sunati - switch
aesay - aerial
Hope it help... Will keep on posting ...........
we will not use this formula for centripetal force cox v changes with the radius. we will use mrw^2 cox mass is constant and w is also constant for every pointI find this question conceptual. Kindly please help:
Question no.1 part.c
Marking scheme says greater the radius, greater will be centripetal force. In the formula: F=mv^2/r centripetal force is INVERSELY proportional to r. So what's going on here?
good question and answer! Just want to note out that;
Omega changes, but not necessarily with radius.good question and answer! Just want to note out that;
Omega isn't constant. There's centripetal acceleration.
The word acceleration denotes that there's rate of change of velocity- i.e. there's rate of change of direction of the object moving in circular motion.
Pls do correct me if I'm wrong.
omega is constant. it does not depend on radius. its a horizontal circle and for horizontal circles, omega is constantgood question and answer! Just want to note out that;
Omega isn't constant. There's centripetal acceleration.
The word acceleration denotes that there's rate of change of velocity- i.e. there's rate of change of direction of the object moving in circular motion.
Pls do correct me if I'm wrong.
Omega does not depend on the radius, that's right. But there's still a centripetal on object right?? And we know, that F= ma, that when there's constant force, there's acceleration of the object. And when you recall the definition of centripetal acceleration, it's the rate of change of angular velocity. Angular velocity, that is omega , is changing at a constant rate. It's changing at a constant rate irrespective of the change of radius. Whether radius changes or not, The angular velocity , omega changes constantly. When omega is constant, there's no centripetal acceleration and with no centripetal acceleration, the object might just not move in a circular motion, but in translatory motion.
umm ok. thnx for the infoOmega does not depend on the radius, that's right. But there's still a centripetal on object right?? And we know, that F= ma, that when there's constant force, there's acceleration of the object. And when you recall the definition of centripetal acceleration, it's the rate of change of angular velocity. Angular velocity, that is omega , is changing at a constant rate. It's changing at a constant rate irrespective of the change of radius. Whether radius changes or not, The angular velocity , omega changes constantly. When omega is constant, there's no centripetal acceleration and with no centripetal acceleration, the object might just not move in a circular motion, but in translatory motion.
Thanks to you- I didn't solve the first part
heheAOA,
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s10_qp_41.pdf
Q3 (b) how do we know that acceleration is of constant magnitude
My guess:
because it is 'g' (acceleration due to gravity) ???
x does change,hehe
The ball then moves
down plane LA and rises up plane RA to its original height.
The key word is right there, to it's original height. a= -(omega )^2 amplitude
In this defining equation of simple harmonic motion, omega is constant throughout the motion of the ball, right?? But accelerations are different at different points of the oscillation. Thus the only other factor, we can see from the equation that changes the acceleration of the ball is x(displacement from the mean position) . X changes and thereby acceleration changes. But in this case, x doesn't change. However they have damped the oscillations, the displacement from the mean position remains constant, that is, acceleration remains , a = -( omega ) ^2 amplitude.
Pls correct me if I'm wrong
oh right
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